PLEASE HELP WITH THIS! if there's is work PLEASE include thank you:) I need # 27 btw

Mathematics

1 answer:

amid [387]3 years ago

8 0

Order.

9, 12, 12, 14, 15, 16, 18, 21

Now split into quarters.

9, 12, 12, 14, 15, 16, 18, 21
| | |
(1) (3)

Determine the values of (1) and (3) by using medians.

14 + 12 + 12 + 9 / 4
47 / 4
approx. 12

So Q1 = 12.

15 + 16 + 18 + 21 / 4
70 / 4
approx. 17

Therefore the answer is C I think. I have not done this ever before. All the knowledge I did was from research lol

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$\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}$

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