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scoundrel [369]
3 years ago
6

Jaqleen can unload a grocery truck twice as fast as Marco. Together, they can unload the truck in 5 hours. How long would it tak

e each of them working alone to unload the truck
(show Your work)
Mathematics
1 answer:
amm18123 years ago
7 0

Jaqleen unloads a truck in x hours and Marco takes 2x hours.

Working together (x*2x) / (x+2x) = 5 hours

2x^2 / 3x = 5  Multiplying both sides by 3x equals 2x^2 -15x = 0

x = 7.5 hours

So Jaqleen takes 7.5 hours and Marco takes 15 hours

Double-Check (7.5 * 15) / (7.5 + 15) = 112.5 / 22.5 equals

5 hours Correct!!


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AlladinOne [14]
X=6
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4 0
3 years ago
The question is in the picture please help fast
Marrrta [24]

Answer:

<em>y = 4x - 57 </em>

Step-by-step explanation:

( x_{1} , y_{1} )

( x_{2} , y_{2} )

m = \frac{y_{2} -y_{1} }{x_{2} -x_{1} }

y - y_{1} = m ( x - x_{1} )

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5 0
3 years ago
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makkiz [27]

Answer:

15p-40

Step-by-step explain

i think is this

8 0
3 years ago
Read 2 more answers
Which is larger 1:40 or 1:60
agasfer [191]
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3 0
3 years ago
Let a, b, c and x elements in the group G. In each of the following solve for x in terms of a, b, and c.
alina1380 [7]

Answer:

The answer is x=a^{-1}cb^{-1}.

Step-by-step explanation:

First, it is important to recall that the group law is not commutative in general, so we cannot assume it here. In order to solve the exercise we need to remember the axioms of group, specially the existence of the inverse element, i.e., for each element g\in G there exist another element, denoted by g^{-1} such that gg^{-1}=e, where e stands for the identity element of G.

So, given the equality axb=c we make a left multiplication by a^{-1} and we obtain:

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xbb^{-1} = a^{-1}cb^{-1}.

Recall that bb^{-1}=e and xe=x. Therefore,

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6 0
3 years ago
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