Check the picture below.
as you recall from the previous exercise, x = 74°, now, using the "inscribed angle theorem" as you saw already, the green intercepted arc is 160°, so y = 160° - 74°.
as far as ∡z, well, we can just use the "inscribed quadrilateral conjecture".
 
        
             
        
        
        
Just around the 15 and 3. So it would be 
(15-3)x4+9=57
This is because (15-3)= 12
12x4=48
48+9= 57 
        
                    
             
        
        
        
If you are proving a congruence of triangles then you need to match the corresponding parts to the triangle you are proving congruent.
BAC would then be congruent to MJR because of the corresponding angles
B is the same angle as M 
A is the same angle as J
C is the same angle as R
 
        
             
        
        
        
The value of k is
<h3>How to solve the simultaneous equation?</h3>
Given:
x-y=k.............(eq i)
2x²+y²-15..............(eq ii)
We would make y the subject formula in eq ii
2x²+y²-15= 0
2x² + y²= 15
y²= 15-2x²
y=  ...........(eq iii)
...........(eq iii)
Substitute the value of y into eq i
x-( = k
= k
x- ( = k
= k
k= 
Read more about simultaneous equations here:
brainly.com/question/16863577
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