Answer:
Graph B
The graph in the attached figure
Step-by-step explanation:
we have

This is a exponential function
of the form

where
a is the initial value
b is the base
r is the rate
b=1+r
In this problem
a=2 ----> the y-intercept
b=3
so
1+r=3 -----> r=3-1=2 -----> r=200%
so
The y-intercept of the graph is equal to 2
As x increases the value of f(x) increases
therefore
Graph B
You can think of this equation as

and thus apply the transformations to it as such



1) D = 2, C = +3
2) D = -12, C = -2
3) C = +6, D = 3
4) C = -7, D = -7