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lana [24]
3 years ago
11

Let T : V → W be a linear transformation from vector space V into vector space W.

Mathematics
1 answer:
wel3 years ago
7 0

Explanation:

Since {v1,...,vp} is linearly dependent, there exist scalars a1,...,ap, with not all of them being 0 such that a1v1+a2v2+...+apvp = 0. Using the linearity of T we have that

a1*T(v1)+a2*T(v1) + ... + ap*T(vp) = T(a1v19+T(a2v2)+...+T(avp) = T(a1v1+a2v2+...+apvp) = T(0) = 0.

Since at least one ai is different from 0, we obtain a non trivial linear combination that eliminates T(v1) , ..., T(vp). That proves that {T(v1) , ..., T(vp)} is a linearly dependent set of W.

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Hello I was wondering if someone would help me with this tricky question?
Rudiy27

Answer:

The two coordinates should be (6, 3) and (10, 4).

Step-by-step explanation:

rise / run

y-value of the 2nd coordinate = 3 + 1 = 4

x-value of the 2nd coordinate = 6 + 4 = 10

The two coordinates should be <u>(6, 3) and (10, 4)</u>.

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3 years ago
For the parallelogram ABCD the extensions of the angle bisectors AG and BH intersect at point P. Find the area of the parallelog
natita [175]

Answer:

The area of a parallelogram is 360 in.²

Step-by-step explanation:

Where DG = GH

GP = 12 in.

AB = 39 in.

∠DAB + ∠ABC = 180° (Adjacent angles of a parallelogram)

Whereby ∠DAB is bisected by AG and ∠ABC is bisected by BH

Therefore, ∠GAB + ∠HBA = 90°

Hence, ∠BPA = 90° (Sum of interior angles of a triangle)

cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{AP}{39} = \dfrac{GP}{GH} =\dfrac{12}{GH}

We note that ∠AGD = ∠GAB (Alternate angles of parallel lines)

∴ ∠AGD = ∠AGD since ∠AGD = ∠GAB (Bisected angle)

Hence AD = DG (Side length of isosceles triangle)

The bisector of ∠ADG is parallel to BH and will bisect AG at point Q

Hence ΔDAQ  ≅ ΔDGQ ≅ ΔGPH and AQ = QG = GP

Hence, AP = 3 × GP = 3 × 12 = 36

cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{36}{39}

\angle GAB = cos^{-1} \left (\dfrac{36}{39}  \right )

∠GAB = 22.62°

cos(\angle GAB) =  \dfrac{36}{39} = \dfrac{12}{GH}

GH =  \dfrac{39}{36} \times {12}

GH = 13 in.

∴ AD 13 in.

BP = 39 × sin(22.62°) = 15 in.

GH = √(GP² + HP²)

∠DAB = 2 × 22.62° = 45.24°

The height of the parallelogram = AD × sin(∠DAB) =  13 × sin(45.24°)

The height of the parallelogram = 120/13 =  9.23 in.

The area of a parallelogram = Base × Height = (120/13) × 39 = 360 in.²

7 0
3 years ago
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Tina wants to buy grass seed to cover her whole lawn, except for the pool. The pool is 7/12 m by 3 /14 m. Find the area the gras
eimsori [14]

Answer:

Since Tina wants to buy grass seed to cover her whole lawn, except for the pool, and the pool is 7/12 m by 3/14 m, to find the area the grass seed needs to cover the following calculation must be performed:

It is impossible to determine the area that the grass seed needs to cover, because we do not have the data of the total size of the lawn. Now, you can determine the size of the surface that should not be covered, which is the one that the pool occupies, namely:

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Answer:

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Step-by-step explanation:

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Aleksandr-060686 [28]

Answer:

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Step-by-step explanation:

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