For every c substitute 4 and for every d substitute -2
c=4
d=-2
6c + 5d - 4c - 3d + 3c - 6d
= 6(4)+ 5(-2)- 4(4)- 3(-2)+ 3(4)- 6(-2)
=24+(-10)-16-(-6)+12-(-12)
=24-10-16+6+12+12
=28
36 take 150-40 then you would want to decide 3 from 110
These two lines are congruent (the same) so we can set them equal to each other and solve.
5x-4=3x+6
The first thing we need to do is subtract 3x from both sides leaving us with 2x-4=6
Now we can add 4 to both sides leaving us with 2x=2
Now we need to divide both sides by 2 to get x alone.
Giving us our final answer of x=1
Subtract 79 from both sides to isolate variable b.
b = 159 - 79
b = 80
Answer:
x=4
Step-by-step explanation:
Consider ΔKLJ:
sinθ=opposite/hypotenuse
sin30=LJ/8√2
LJ=0.5*8√2=4√2
Consider ΔMLJ:
sinθ=opp/hyp
sin45=x/4√2
1/√2=x/4√2
4√2/√2=x
x=4