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pochemuha
3 years ago
10

Draw a line say ab take point c out of it through c draw a line parellel to ab using compass and ruler only

Mathematics
1 answer:
nata0808 [166]3 years ago
4 0

Answer:

give me brainliest

Given a line AB with Point C outside it.

Mark point D on the line AB. Join CD

With D as center, and any radius, draw an arc intersecting AB at E, and CD at F.

With C as center, and same radius as before, draw an arc intersecting CD at G.

Open a compass to length EF

Now,with G as center, and compass opened the same radius as before, draw an arc intersecting the previous arc at H.

Draw a line m passing through C and H.

Thus m is the line parallel to AB, and passing through point C

∴m∣∣AB

Step-by-step explanation:

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5d-2g=9 

-2g=9-5d 

g=- \dfrac{9-5d}{2}
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3 years ago
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One positive number is three more than twice another. If their product is 629, find the numbers.
sineoko [7]

Answer:

x = 17 and y = 37

Step-by-step explanation:

Let the numbers be x and y.

y = 3 + 2x

xy = 629

substituting y in the second equation we get

x(3+2x) = 629

3x + 2x^{2} = 629

2x^{2} + 3x - 629 = 0

Solving a quadratic equation by using its formula:

x = [-3 ±√(9-4(2)(-629)] / 4

x = [-3 ± √5041] / 4

x = [-3 ± 71] / 4

x = 17 and \frac{-37}{2}

Ignore the negative number in x and just use x = 17 in the first equation we get

y = 3 + 2(17) = 37

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4 years ago
Help me with this problem
kozerog [31]

Answer:

The slope is 8

Step-by-step explanation:

because the line is intercepting is the 8

8 0
3 years ago
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Please help me I’ll mark you as brainliest! Answer quickly pleaseee
Scrat [10]

Answer:

i need the triangle

Step-by-step explanation:

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3 years ago
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Sloan [31]

Answer:

Sum of \frac{7x}{x^2-4} and \frac{2}{x+2} is \mathbf{\frac{9x-4}{x^2-4}}

Option B is correct answer.

Step-by-step explanation:

We need to find sum of \frac{7x}{x^2-4} and \frac{2}{x+2}

Finding sum of  \frac{7}{x^2-4} and \frac{2}{x+2}:

\frac{7x}{x^2-4}+\frac{2}{x+2}

We know that x^2-4 =(x+2)(x-2)

Replacing x^2-4

\frac{7x}{(x+2)(x-2)}+\frac{2}{x+2}

Now, taking LCM of (x+2)(x-2) and (x+2) we get (x+2)(x-2)

=\frac{7x+2(x-2)}{(x+2)(x-2)}\\=\frac{7x+2x-4}{(x+2)(x-2)}\\=\frac{9x-4}{(x+2)(x-2)}\\=\frac{9x-4}{x^2-4}

So, Sum of \frac{7x}{x^2-4} and \frac{2}{x+2} is \mathbf{\frac{9x-4}{x^2-4}}

Option B is correct answer.

6 0
3 years ago
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