To find the slope you use the slope formula y2-y1 / x2-x1. So use two point on the line we will make ours (1,2) and (3,4). Substitute to make 4-2 / 3-1 = 1/1 so using the rise over run method. The line rises up one and runs by one. The slash mark means divide, it's easiest in a fraction.
Also if you come across the equation y=mx+b, m is the slope and b is the y-intercept, this is called slope intercept formula.
When Javier writes 40 on both accounts they cost him the same amount of money so it should be 41.
Javier needs to write 41 checks for the second bank to beat better
Step-by-step explanation:
R = 6.5cm and r = 2.3 cm
area of the shaded region = area of the outer circle - area of the inner circle
= πR²-πr²
=π(R²-r²)
=π{(6.5)²-(2.3)²}
=π (42.25-5.29)
= 3.14× 36.96
= 115.866
= 116 cm²
The greatest common factor of this can be solved by looking at the individual parts and splitting it up.
First, we have 28 and 7. Well, thats an easy one. 7 goes into 28 4 times so we are now left with 4 and 1.
We can also write the rest of this like this 4(x*x*y) - 1(x*y*y*y*y*y)
Now, what values are in both equations. We have one x and one y that can be taken out of both.
We end up with 7xy(4x-7y^4)
Answer:
Rs. 612,480
Step-by-step explanation:
Hi there,
Here the question asks us to find the cost of leveling a badminton court at the rate of Rs.80 per sq..
So by the word leveling we know that we have to find the area of the court in order to proceed further.
<em>(I am assuming the court to be rectangular in shape).</em>
Area of a rectangle = Length * Breadth
*Length = 132 meters
*Breadth = 58 meters
==> 132*58= 7656 m^2
So now that we got the area of the badminton court lets find the cost of leveling it ==>
Cost of leveling per meter^2 = Rs. 80
Area = 7656 m^2
==> 7656 * 80 = 612,480
So the cost would be <u>Rs. 612,480</u>
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