Answer:
<h3>A) 204m</h3><h3>B) 188m</h3>
Step-by-step explanation:
Given the rocket's height above the surface of the lake given by the function h(t) = -16t^2 + 96t + 60
The velocity of the rocket at its maximum height is zero
v = dh/dt = -32t + 96t
At the maximum height, v = 0
0 = -32t + 96t
32t = 96
t = 96/32
t = 3secs
Substitute t = 3 into the modeled function to get the maximum height
h(3) = -16(3)^2 + 96(3) + 60
h(3) = -16(9)+ 288 + 60
h(3) = -144+ 288 + 60
h(3) = 144 + 60
h(3) = 204
Hence the maximum height reached by the rocket is 204m
Get the height after 2 secs
h(t) = -16t^2 + 96t + 60
when t = 2
h(2) = -16(2)^2 + 96(2) + 60
h(2) = -64+ 192+ 60
h(2) = -4 + 192
h(2) = 188m
Hence the height of the rocket after 2 secs is 188m
Answer:
9 cups
Step-by-step explanation:
6 ÷ 2/3
6/1 ÷ 2/3
6/1 x 3/2 = 18/2 = 9/1 = 9
Answer:
11
Step-by-step explanation:
11*2=22, 22+14=36, quick maths
Answer:
The diameter is 6 yards.
Step-by-step explanation:
2pir=18.84
pir=9.42
r=3(nearest whole number)
d=2r
d=2*3
d=6
Therefore, the diameter is 6 yards.
There is a 1 in 15 chance it could occur. The more numbers you add, the rarer the chance. This does not guarantee that it will occur in 15 tests.