1.c
3.c 153
These are the ones that I could solve
Answer:
See below in bold,.
Step-by-step explanation:
There are 30-17 = 13 boys in the class.
a. Prob(First is a boy ) = 13/30 and Prob( second is a boy = 12/29).
As these 2 events are independent:
Prob( 2 boys being picked) = 13/30 * 12/29 = 26/145 or 0.179 to the nearest thousandth.
b. By a similar method to a:
Prob ( 2 girls being picked) = 17/30 * 16/29 = 136/435 = 0.313 to the nearest thousandth.
c. Prob (First student is a boy and second is a girl) = 13/30 * 17/29 = 221/870.
Prob ( first student is a girl and second is a boy) = 17/30 * 13/29 = 221/870
These 2 events are not independent so they are added:
Prob( one of the students is a boy) = 2 (221/870 = 221/435 = 0.508 to the nearest thousandth.
Answer:
f(-2) = 0
f(1) = 12
(x^3 - 7x - 6) / (x + 2) = x^2 - 2·x - 3 = (x - 3)(x + 1)
x^3 - 7x - 6 = (x + 2)(x - 3)(x + 1)
Answer:
13sqrt(2)
Step-by-step explanation:
Using pythagoras theorem
Answer:
8
Step-by-step explanation:
Isolate and solve for C
