Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean 
and standard deviation 
is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:
The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:
X = 590:
Z = 0.76
Z = 0.76 has a p-value of 0.7764.
X = 400:
Z = -0.89
Z = -0.89 has a p-value of 0.1867.
0.7764 - 0.1867 = 0.5897 = 58.97%.
58.97% of students would be expected to score between 400 and 590.
More can be learned about the normal distribution at brainly.com/question/27643290
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Population mean = (7+8+6+6+6+4+4+1+2+7+6+1+1+1+3+3+5+4+5+7) / 20 = 87/20 = 4.35 <==
sample mean = (4+5+7) / 3 = 16/3 = 5.33 <==
Answer:
See image
Step-by-step explanation:
To graph the inequality
-2x + y >= -10
Change it to y = mx + b form, use a solid line (bc of the "or equal to" underline)
y >= 2x - 10 We have y-intercept at -10 and slope 2/1, shading goes above the line.
The other graph is an absolute value graph; it has a v-shape. The 7 makes it stretched 7 times taller (and skinnier) the -4 by the x shifts the whole graph to the right 4 units. The -4 at the end of the equation shifts the whole graph down 4 units. See image. The shading goes above the V (kind of looks like inside)
The solution to the system is where the shading of the two overlap. It is mostly the shading for the absolute value graph except for a tiny triangle at the bottom. See image.
Answer:
a) y> -5x+3
is what represents the shaded area
