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Rashid [163]
3 years ago
7

WILL GIVE BRAINLIEST!! NEED SOLVING ASAP!!! One night two cylindrical wax candles of different heights and different diameters w

ere lit. One of the candles was 20 cm taller than the other. They were both lit at the same time and each burned at a steady rate. Five hours after they were lit they were both the same height. The taller one burned all of its wax six hours after it was lit, and the shorter one burned all of its wax 10 hours after it was lit. What was the ratio of the original height of the shorter candle to the original height of the taller candle? Express your answer as a common fraction.
Mathematics
1 answer:
Svetllana [295]3 years ago
8 0

Answer:

Step-by-step explanation:

T= tall candle

t= short candle

B and b be their speed of burning (in/hr)

T = 6 * B t = 10 b

T – 5 B = t – 5 b

T – 5 * T/6 = t – 5 * t/10

1/6 T = ½ t t/T = 1/3

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