Question

Liquid bromine is added to sodium iodide crystals

Answer 1

The following chemical reaction will occur:

Br₂ (l) + 2 NaI (s) → 2 NaBr (s) + I₂ (s)

Explanation:

Because the bromide (Br₂) have a higher reactivity than iodide (I₂) it is able the remove the iodide from its salts. So the bromide will react with sodium iodine (NaI) to produce sodium bromide (NaBr) and iodine.

The chemical reaction is:

Br₂ (l) + 2 NaI (s) → 2 NaBr (s) + I₂ (s)

where:

(l) - liquid

(s) - solid

Learn more about:

balancing chemical equations

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