All categories

3 years ago

Fill in the relative frequency for each group. (Round your answers to four decimal places.)

Mathematics

1 answer:

zheka24 [161]3 years ago

7 0

Answer:

Singles

Amount ($) Frequency Relative Frequency

51-100 4 0.069

101-150 11 0.1897

151-200 14 0.2414

201-250 14 0.2414

251-300 11 0.1897

301-350 4 0.069

Couples

Amount ($) Frequency Relative Frequency

100-150 5 0.0676

151-200 5 0.0676

201-250 5 0.0676

251-300 5 0.0676

301-350 11 0.1486

351-400 11 0.1486

401-450 11 0.1486

451-500 11 0.1486

501-550 5 0.0676

551-600 5 0.0676

Step-by-step explanation:

The relative frequency can be computed by dividing each frequency by the sum of frequency i.e. Relative frequency=f/sum(f)

Singles

Amount ($) Frequency Relative Frequency

51-100 4 4/58=0.069

101-150 11 11/58=0.1897

151-200 14 14/58=0.2414

201-250 14 14/58=0.2414

251-300 11 11/58=0.1897

301-350 4 4/58=0.069

Total 58 1

Couples

Amount ($) Frequency Relative Frequency

100-150 5 5/74=0.0676

151-200 5 5/74=0.0676

201-250 5 5/74=0.0676

251-300 5 5/74=0.0676

301-350 11 11/74=0.1486

351-400 11 11/74=0.1486

401-450 11 11/74= 0.1486

451-500 11 11/74=0.1486

501-550 5 5/74=0.0676

551-600 5 5/74=0.0676

Total 74 1

You might be interested in

Givin the equilateral triangle below find the value of y

VladimirAG [237]

Answer:

15°

Step-by-step explanation:

All angles in an equilateral triangle are equal.

Angle sum property of triangle = 180°

<1 + <2 + <3 = 180°

<1 = <2 = <3 = 60°

4y = 60

y = 60/4

y = 15°

4 0

3 years ago

Two people are driving to work at different constant speeds. The graph below shows the distance traveled over time by driver 1.

Luden [163]

Answer:

5 mph

Step-by-sep explanation:

To find of out the difference between the speed of the two drivers in miles per hour (not in miles per minute), first, calculate the unit rate or speed of driver 1 using the graph, and driver 2 using the table given.

Unit rate/speed = distance travelled/time = y/x.

Speed of Driver 1/unit rate:

The graph shows 1.5 miles (y) is travelled in 2 minutes (x).

Convert the 2 minutes to hour, you will have:

$\frac{2}{60} = \frac{1}{30} hr$

Speed in mph = $\frac{y}{x} = \frac{1.5}{\frac{1}{30}} = 1.5*\frac{30}{1} = 45$

Speed of Driver 1 in mph = 45 mph

Speed of Driver 2/unit rate:

The table shows 2.5 miles (y) is travelled in 3 minutes (x).

Convert the 3 minutes to hour, you will have:

$\frac{3}{60} = \frac{1}{20} hr$

Speed in mph = $\frac{y}{x} = \frac{2.5}{\frac{1}{20}} = 2.5*\frac{20}{1} = 50$

Speed of Driver 2 in mph = 50 mph

Difference between the speed of the two drivers = 50 - 45 = 5 mph

4 0

4 years ago

The planet mercury is approximately 6×10 to the 7th miles from the sun. The distance between the sun and mars is approximately 2

4vir4ik [10]

Mars is 2×10⁸/6×10⁷=20×10⁷/6×10⁷=20/6=10/3=3.3 times farther from the sun than Mercury.

8 0

3 years ago

PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Softa [21]

$180^o-112^o=68^o$

$\left\{\begin{array}{ccc}2x+3y=68&|\cdot(-15)\\30x+11y=112\end{array}\right\\\underline{+\left\{\begin{array}{ccc}-30x-45y=-1020\\30x+11y=112\end{array}\right}\\.\ \ \ \ \ \ \ -34y=-908\ \ \ |:(-34)\\\\.\ \ \ \ \ \ \ \ \ \ \ y=\dfrac{908}{34}\to y=\dfrac{454}{17}\\\\2x+3\cdot\dfrac{454}{17}=68\ \ \ \ |\cdot17\\\\34x+1362=1156\ \ \ \ |-1362\\34x=-206\ \ \ \ |:34\\\\x=-\dfrac{206}{34}\to x=-\dfrac{103}{17}\\\\ \left\{\begin{array}{ccc}x=-\dfrac{103}{17}\\\\y=\dfrac{454}{17}\end{array}\right$

8 0

3 years ago

Is the statement H0 : µ = 9 a valid null hypothesis? Group of answer choices Yes, this is a statement that compares a parameter

Nuetrik [128]

Answer:

No, there is no parameter contained in this statement

Step-by-step explanation:

Given that H0 : µ = 9

We have to check whether this is a valid null statement

Normally null hypothesis would have equal to sign and the value to be tested would be a statistic i.e. a measure characteristic of a sample.

So we create null hypothesis as sample mean = 9 or \mu or sample std deviation and so on.

Here population parameter mu is equated to 9

Hence not a valid null hypothesis.

No, there is no parameter contained in this statement

8 0

4 years ago