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3 years ago

Two people are driving to work at different constant speeds. The graph below shows the distance traveled over time by driver 1.

Mathematics

1 answer:

Luden [163]3 years ago

4 0

Answer:

5 mph

Step-by-sep explanation:

To find of out the difference between the speed of the two drivers in miles per hour (not in miles per minute), first, calculate the unit rate or speed of driver 1 using the graph, and driver 2 using the table given.

Unit rate/speed = distance travelled/time = y/x.

Speed of Driver 1/unit rate:

The graph shows 1.5 miles (y) is travelled in 2 minutes (x).

Convert the 2 minutes to hour, you will have:

$\frac{2}{60} = \frac{1}{30} hr$

Speed in mph = $\frac{y}{x} = \frac{1.5}{\frac{1}{30}} = 1.5*\frac{30}{1} = 45$

Speed of Driver 1 in mph = 45 mph

Speed of Driver 2/unit rate:

The table shows 2.5 miles (y) is travelled in 3 minutes (x).

Convert the 3 minutes to hour, you will have:

$\frac{3}{60} = \frac{1}{20} hr$

Speed in mph = $\frac{y}{x} = \frac{2.5}{\frac{1}{20}} = 2.5*\frac{20}{1} = 50$

Speed of Driver 2 in mph = 50 mph

Difference between the speed of the two drivers = 50 - 45 = 5 mph

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2 years ago

1) Given: circle k(O), ED= diameter ,m∠OEF=32°, m(arc)EF=(2x+10)° Find: x

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$m\widehat{DF}=360^\circ-180^\circ-(2x+10)^\circ=(170-2x)^\circ$

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$m\angle DOF=2m\angle OEF=64^\circ$

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###

2. Arc FE and angle EOF have the same measure, 56 degrees. By the inscribed angle theorem,

$m\angle EOF=2m\angle EDF\implies56^\circ=2m\angle EDF\implies m\angle EDF=28^\circ$

Triangle DEF is isosceles because FD and ED have the same length, so angles EFD and DEF are congruent. Also, the sum of the interior angles of any triangle is 180 degrees. It follows that

$m\angle EFD+m\angle EDF+m\angle DEF=180^\circ\implies\boxed{m\angle EFD=76^\circ}$