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Arada [10]
3 years ago
5

Find the equation of the line which passes through the point (-4,12) and is perpendicular to the given line. Express your answer

in slope intercept form. The slope is -7
Mathematics
1 answer:
Vika [28.1K]3 years ago
8 0

Answer:

y = 1/7x + 88/7

Step-by-step explanation:

y = mx +b

since it is perpendicular you have to get the negative reciprocal of the slope which is 1/7

y = 1/7x + b then you would plug in your points

12 = 1/7(-4) + b and then solve for b

12 = -4/7 + b

+ 4/7

88/7 = b

y = 1/7x + 88/7

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Line b passes through the Point(-3, -4) and has a slope of -1/2. What is the equation of Line b in standard form?
Anna11 [10]

Answer:

x+2y=-11

Step-by-step explanation:

Slope intercept form of a line is given by:

y=mx+b

Where

m is the slope and b is the y-intercept

Given slope is  -\frac{1}{2}

We can write:

y=-\frac{1}{2}x+b

Now to find b, we replace x with -3 and y with -4, given, so we have:

y=-\frac{1}{2}x+b\\-4=-\frac{1}{2}(-3)+b\\-4=\frac{3}{2}+b\\b=-5.5

So, the equation is:

y=-\frac{1}{2}x-\frac{11}{2}

Now,

The standard form is given by:

Ax+By=C

So, we take x and y to left side and the constant to right side. Rearranging, we get:

y=-\frac{1}{2}x-\frac{11}{2}\\2y=-x-11\\x+2y=-11

The first answer choice is right.

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3 years ago
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I know the answers but I hate simplifying
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8 0
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An arithmetic sequence with a thrid term of 8 and constant difference of 5
olga nikolaevna [1]
\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
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n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
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a_3=8\\
n=3
\end{cases}
\\\\\\
a_3=a_1+(3-1)5\implies 8=a_1+(2)5\implies 8=a_1+10
\\\\\\
\boxed{-2=a_1}
\\\\\\
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Zepler [3.9K]

Answer:

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5 0
3 years ago
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