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3 years ago

Assume that all intersecting sides meet at right angles

Mathematics

1 answer:

givi [52]3 years ago

8 0

Answer:

Step-by-step explanation:

15-9

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What is 11.45 as a fraction

Viefleur [7K]

11.45

the 11 is ur whole number...it stays ur whole number
the 0.45 is ur fraction...and since the last number (5) is in the hundredths place, put it over 100
so u now have : 11 45/100 which reduces to 11 9/20 and if u need it in improper fraction form, it is 229/20

6 0

3 years ago

Read 2 more answers

Ray had 60 football cards last year.This year he has 200. Find the percent of change

bulgar [2K]

Answer:70%

Step-by-step explanation: no. of cards last year=60

no. of cards presently=200

increase in no. of cards=200-60

=140

%change=140/200 x 100

7 0

2 years ago

Find the length of side X

mel-nik [20]

Solve using the Pythagorean theorem.

The hypotenuse is c.

5 0

2 years ago

Identify the center of the circle.<br> Center=? <br> Help pls!!!<br> *its hw*

Elenna [48]

Answer:

the center of the circle seems to be at E

Step-by-step explanation:

this however is a guess, tell me if I'm right

4 0

3 years ago

12% of children are nearsighted, but this condition often is not detected until they go to kindergarten. A school district tests

Klio2033 [76]

Answer:

There is a 34.60% probability that 0 or 1 of them is nearsighted.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they are nearsighted, or they are not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem, we have that:

12% of children are nearsighted. This means that $p = 0.12$ .

A school district tests all incoming kindergarteners' vision. In a class of 18 kindergarten students, what is the probability that 0 or 1 of them is nearsighted?

There are 18 students, so $n = 18$