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insens350 [35]
3 years ago
11

Assume that all intersecting sides meet at right angles

Mathematics
1 answer:
givi [52]3 years ago
8 0

Answer:

6

Step-by-step explanation:

15-9

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Is that rational or irrational
creativ13 [48]
Irrational

We know that pi is irrational (we can’t express it as a ratio of two numbers), and we are multiplying it by a rational number (-2). However -2 lots of something with infinite digits, will still have infinite digits, therefore it is irrational.
3 0
3 years ago
The length of a rectangle is 6 in longer than its width.if the perimeter of the rectangle is 68in find the length and width ?
wel

The length and the width of the rectangle are 20 and 14 inches respectively

<h3>How to find the length and width?</h3>

The given parameters are:

Length = 6 + Width

Perimeter = 68 inches

The perimeter of a rectangle is calculated as:

Perimeter = 2 * (Length + Width)

So, we have:

2 * (Length + Width) = 68

Divide both sides by 2

Length + Width = 34

Substitute Length = 6 + Width in Length + Width = 34

6 + Width + Width = 34

Evaluate the like terms

2 * Width = 28

Divide both sides by 2

Width = 14

Substitute Width = 14 in Length = 6 + Width

Length = 6 + 14

Evaluate

Length = 20

Hence, the length and the width of the rectangle are 20 and 14 inches respectively

Read more about perimeter at:

brainly.com/question/24571594

#SPJ1

6 0
1 year ago
an angle measures 62 degrees less than the measure of its complementary angle. what is the measure of each angle
Yuki888 [10]

Answer:

Step-by-step explanation:

What is a complementary angle?

3 0
2 years ago
A car has a windshield wiper on the driver's side that has total arm length of 10 inches. It rotates
son4ous [18]

Answer:

75.44 Square Inches

Step-by-step explanation:

The diagram of the problem is produced and attached.

To determine the area of the cleaned sector:

Let the radius of the larger sector be R

Let the radius of the smaller sector be r

Area of the larger sector =\frac{\theta}{360}X\pi R^2

Area of the smaller sector =\frac{\theta}{360}X\pi r^2

Area of shaded part =Area of the larger sector-Area of the smaller sector

=\frac{\theta}{360}X\pi R^2-\frac{\theta}{360}X\pi r^2\\=\frac{\theta \pi}{360}X (R^2- r^2)

From the diagram, R=10 Inch, r=10-7=3 Inch, \theta=95^\circ

Therefore, Area of the sector cleaned

=\frac{95 \pi}{360}X (10^2- 3^2)\\=75.44$ Square Inches

7 0
3 years ago
The table represents a function.
Maslowich

-1

Step-by-step explanation:

..................

3 0
2 years ago
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