Help with this question please thank you so much

How long, in minutes, does it take to cover 24 miles at a rate of 12 miles per hour?

frutty [35]

It would take 120 minutes

4 0

3 years ago

A pencil has a mass of 25 grams. An apple a mass that is 75 grams more than the pencil has What is the mass of the apple, in gra

butalik [34]

The apple weighs 100 grams

5 0

3 years ago

Read 2 more answers

3.2 geometry worksheet

alekssr [168]

Answer/Step-by-step explanation:

5. 21x + 4 = 22x - 2 (corresponding angles)

Collect like terms

21x - 22x = -4 - 2

-x = -6

divide both sides by -1

x = 6

6. (x + 72) + (x + 132) = 180 (linear pair)

x + 72 + x + 132 = 180

Add like terms

2x + 204 = 180

2x = 180 - 204

2x = -24

x = -12

7. 90 = 22x + 2 (vertical angles)

90 - 2 = 22x

88 = 22x

Divide both sides by 22

4 = x

x = 4

8. 12x + 10 = 13x + 3 (vertical angles)

Collect like terms

12x - 13x = -10 + 3

-x = -7

Divide both sides by -1

x = 7

9. 17x = 16x + 5 (alternate exterior angles)

17x - 16x = 5

x = 5

✔️17x

Plug in the value of x

17(5) = 85°

10. 21x - 6 = 20x (corresponding angles)

Add like terms

21x - 20x = 6

x = 6

✔️20x

20(6) = 120°

3 0

3 years ago

The difference between the two roots of the equation 3x^2+10x+c=0 is 4 2/3 . Find the solutions for the equation.

andrezito [222]

Answer:

Given the equation: $3x^2+10x+c =0$

A quadratic equation is in the form: $ax^2+bx+c = 0$ where a, b ,c are the coefficient and a≠0 then the solution is given by :

$x_{1,2} = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$ ......[1]

On comparing with given equation we get;

a =3 , b = 10

then, substitute these in equation [1] to solve for c;

$x_{1,2} = \frac{-10\pm \sqrt{10^2-4\cdot 3 \cdot c}}{2 \cdot 3}$

Simplify:

$x_{1,2} = \frac{-10\pm \sqrt{100- 12c}}{6}$

Also, it is given that the difference of two roots of the given equation is $4\frac{2}{3} = \frac{14}{3}$

i.e,

$x_1 -x_2 = \frac{14}{3}$

Here,

$x_1 = \frac{-10 + \sqrt{100- 12c}}{6}$ , ......[2]

$x_2= \frac{-10 - \sqrt{100- 12c}}{6}$ .....[3]

then;

$\frac{-10 + \sqrt{100- 12c}}{6} - (\frac{-10 + \sqrt{100- 12c}}{6}) = \frac{14}{3}$

simplify:

$\frac{2 \sqrt{100- 12c} }{6} = \frac{14}{3}$

or

$\sqrt{100- 12c} = 14$

Squaring both sides we get;

$100-12c = 196$

Subtract 100 from both sides, we get

$100-12c -100= 196-100$

Simplify:

-12c = -96

Divide both sides by -12 we get;

c = 8

Substitute the value of c in equation [2] and [3]; to solve $x_1 , x_2$

$x_1 = \frac{-10 + \sqrt{100- 12\cdot 8}}{6}$

or

$x_1 = \frac{-10 + \sqrt{100- 96}}{6}$ or

$x_1 = \frac{-10 + \sqrt{4}}{6}$

Simplify:

$x_1 = \frac{-4}{3}$

Now, to solve for $x_2$ ;

$x_2 = \frac{-10 - \sqrt{100- 12\cdot 8}}{6}$

or

$x_2 = \frac{-10 - \sqrt{100- 96}}{6}$ or

$x_2 = \frac{-10 - \sqrt{4}}{6}$

Simplify:

$x_2 = -2$

therefore, the solution for the given equation is: $-\frac{4}{3}$ and -2.

3 0

3 years ago

Factor the trinomial below.<br> x2 + 14x + 48

elixir [45]

IF IT EQUALS 0
1. find two number that multiplied to 48 and adds to 14, which are 6 and 8.

2. substitute the new numbers in with x to get x^2 + 6x + 8x + 48.

3. factor out the x and the 8 to get x(x+6)+8(x+6).

4. x = -6, x = -8

IF IT DOES NOT EQUAL 0
then (x+6)*(x+8) is your answer.

4 0

4 years ago