Answer: ABCD is a quadrilateral
To prove : ∠AOB=
2
1
(∠C+∠D)
AO and BO is bisector of A and B
∠1=∠2∠3=∠4...(1)
∠A+∠B+∠C+∠D=360
(Angle sum property)
2
1
(∠A+∠B+∠C+∠D)=180...(2)
In △AOB
∠1+∠3+∠5=
2
1
(∠A+∠B+∠C+∠D)
∠1+∠3+∠5=∠1+∠3+
2
1
(∠C+∠D)
∠AOB=
2
1
(∠C+∠D)
Explanation: In a quadrilateral ABCD. AO and BO are bisectors of angle A and angle B respectively. Prove that ∠AOB=
2
1
{∠C+∠D}.
Answer:
-3165
Step-by-step explanation:
put 3 in for x than you just multiply from there than once you multiplied add and subtract than you have the answer
Answer:
Exact form: 11/2
Decimal form: 5.5
Mixed number form: 5 1/2
Step-by-step explanation:
Hi, to begin, the ordered pair value (-3, 15) has an x-value of -3. So, to see if it lies on the line of your equation y = 6x + 11, plug -3 in for x. This gives you y = 6(-3) + 11 = -7 So the ordered pair answer for this would be (-3, -7) and not (-3, 15). So the answer is no.
The first one is (-2,1)
The other one is 36
