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Zinaida [17]
2 years ago
13

Drag the tiles to the boxes to complete the pairs. Not all tiles will be used.

Mathematics
1 answer:
bagirrra123 [75]2 years ago
3 0

Answer:

Hope that this is helpful.

Step-by-step explanation:

7,11,15,19 - 16,20,24,28(add 4 )

7+4=11. 16+4=20

11+4=15. 20+4=24

15+4=19. 24+4=28

12,24,48,96 - 31,62,124,248(multiply 2)

12×2=24. 31×2=62

24×2=48. 62×2=124

48×2=96. 124×2=248

13,15,17,19 - 132,134,136,138(add 2)

13+3=15. 132+2=134

15+2=17. 134+2=136

17+2=19. 136+2=138

3,12,48,193 - 7,28,112,448(multiply 4)

3×4=12. 7×4=28

12×4=48. 28×4=112

48×4=193. 112×4=448

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A jet moving at constant speed traveled 6,600 km in 3 hours. What was the speed of the jet?
DanielleElmas [232]

Answer:

The speed of the jet is 2,200\frac{km}{h}

Step-by-step explanation:

The speed traveled by the jet can be found using the relationship between distance and time. Because the problem gives the values for distance and time, they must be replaced in the equation and in this way the requested speed will be found.

1. Write the general equation for the speed:

Speed=\frac{Distance}{Time}

2. Replace the values of distance and time on the general equation for the speed and make the mathematical operations:

Speed=\frac{6,600km}{3hours}

Speed=2,200\frac{km}{h}

Therefore the speed of the jet is 2,200\frac{km}{h}

3 0
3 years ago
Read 2 more answers
10
Novay_Z [31]

Answer:

The sequence of transformations that maps ΔABC to ΔA'B'C' is the reflection across the <u>line y = x</u> and a translation <u>10 units right and 4 units up</u>, equivalent to T₍₁₀, ₄₎

Step-by-step explanation:

For a reflection across the line y = -x, we have, (x, y) → (y, x)

Therefore, the point of the preimage A(-6, 2) before the reflection, becomes the point A''(2, -6) after the reflection across the line y = -x

The translation from the point A''(2, -6) to the point A'(12, -2) is T(10, 4)

Given that rotation and translation transformations are rigid transformations, the transformations that maps point A to A' will also map points B and C to points B' and C'

Therefore, a sequence of transformation maps ΔABC to ΔA'B'C'. The sequence of transformations that maps ΔABC to ΔA'B'C' is the reflection across the line y = x and a translation 10 units right and 4 units up, which is T₍₁₀, ₄₎

5 0
2 years ago
5. Luis found a new text messaging plan which will charge him $2.00 for 80 messages. Using this
Pavel [41]
I think that Luis would have to pay $22.50
7 0
2 years ago
What is the first step in solving ln(x − 1) = ln6 − lnx for x?
Stels [109]

Answer:

Option C - Simplify the right side using the "difference of two logs is the log of the quotient" property.

Step-by-step explanation:

Given : Expression \ln (x-1)=\ln 6-\ln x

To find : What is the first step in solving  the expression ?

Solution :

Expression \ln (x-1)=\ln 6-\ln x

Step 1 - Simplify the right side using the "difference of two logs is the log of the quotient" property.

i.e. \ln a-\ln b=\ln(\frac{a}{b})

Apply the first step we get,

\ln (x-1)=\ln(\frac{6}{x})

Therefore, Option C is correct.

6 0
3 years ago
Find the amount of money a woman owes at the end of 3 years if 5% interest is compounded continuously on her $2500 debt
stepladder [879]

Answer:

$ 2904.59

Step-by-step explanation:

For CONTINUOUS compounding    FV = PV e^it

FV = future value    PV = present value   i = decimal interest   t = years

FV = 2500 e^(.05 * 3) = 2904.59

5 0
2 years ago
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