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DochEvi [55]
3 years ago
14

Laryngeal cancer rates in smokers is 160.0 (per 100,000) and 25.0 (per 100,000) among nonsmokers. Among smokers, what percentage

of laryngeal cancer cases are due to the exposure (smoking)?
Mathematics
1 answer:
Romashka [77]3 years ago
4 0

Answer:

0.16%

Step-by-step explanation:

From the statement of the question;

Number of Laryngeal cancer due to smoking = 160

Population of smokers = 100,000

Hence the percentage of smokers liable to have Laryngeal cancer = 160/100000 ×100/1

=0.16%

Hence 0.16% of smokers are liable to Laryngeal cancer

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Rewrite 3/35 and 1/10 so they have common denominators
Aleks [24]

Answer:

\frac{6}{70} and \frac{7}{70}

Step-by-step explanation:

The LCM of 35 and 10 is 70.

35×2=70

10×7=70

You got to multiply 3 with 2 and 1 with 7 to make 6/70 and 7/70.

5 0
2 years ago
The length of human pregnancies from conception to birth follows a distribution with mean 266 days and standard deviation 15 day
Katena32 [7]

Answer:

a) 81.5%

b) 95%

c) 75%

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 266 days

Standard Deviation, σ = 15 days

We are given that the distribution of  length of human pregnancies is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(between 236 and 281 days)

P(236 \leq x \leq 281)\\\\= P(\displaystyle\frac{236 - 266}{15} \leq z \leq \displaystyle\frac{281-266}{15})\\\\= P(-2 \leq z \leq 1)\\\\= P(z \leq 1) - P(z < -2)\\= 0.838 - 0.023 = 0.815 = 81.5\%

b) a) P(last between 236 and 296)

P(236 \leq x \leq 281)\\\\= P(\displaystyle\frac{236 - 266}{15} \leq z \leq \displaystyle\frac{296-266}{15})\\\\= P(-2 \leq z \leq 2)\\\\= P(z \leq 2) - P(z < -2)\\= 0.973 - 0.023 = 0.95 = 95\%

c) If the data is not normally distributed.

Then, according to Chebyshev's theorem, at least 1-\dfrac{1}{k^2}  data lies within k standard deviation of mean.

For k = 2

1-\dfrac{1}{(2)^2} = 75\%

Atleast 75% of data lies within two standard deviation for a non normal data.

Thus, atleast 75% of pregnancies last between 236 and 296 days approximately.

7 0
2 years ago
PLEASE HELP! WILL MARK BRAINLIEST!!
adoni [48]

Answer:

41.04 meters

Step-by-step explanation:

The questions which involve calculating the angles and the sides of a triangle either require the sine rule or the cosine rule. In this question, the two sides that are given are adjacent to each other the given angle is the included angle. The initial position is given by A. The tree is denoted as C and the fence post is denoted as B. Since the use of sine rule will complicate the question, it will be easier to solve this question using the cosine rule. Therefore, cosine rule will be used to calculate the length of BC. The cosine rule is:

BC^2 = AB^2 + AC^2 - 2*AB*AC*cos(BAC).

The question specifies that AC = 70 meters, BAC = 25°, and AB = 35 meters. Plugging in the values:

BC^2 = 35^2 + 70^2 - 2(35)(70)*cos(25°).

Simplifying gives:

BC^2 = 1684.091844.

Taking square root on the both sides gives BC = 41.04 meters (rounded to two decimal places).

Therefore, the distance between the point on the tree to the point on the fence post is 41.04 meters!!!

6 0
3 years ago
Find the missing length indicated.<br> 18<br> ?<br> 4<br> 8<br> A) 21<br> C) 9<br> B) 3<br> D) 25
Reika [66]
I think the answer is 9
8 0
2 years ago
HELP ME PLEASE!!!! I NEED HELP!!!!!
ehidna [41]
I'm pretty sure the answer is A. hope that helped
8 0
2 years ago
Read 2 more answers
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