Answer:
and 
Step-by-step explanation:
The LCM of 35 and 10 is 70.
35×2=70
10×7=70
You got to multiply 3 with 2 and 1 with 7 to make 6/70 and 7/70.
Answer:
a) 81.5%
b) 95%
c) 75%
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 266 days
Standard Deviation, σ = 15 days
We are given that the distribution of length of human pregnancies is a bell shaped distribution that is a normal distribution.
Formula:

a) P(between 236 and 281 days)

b) a) P(last between 236 and 296)

c) If the data is not normally distributed.
Then, according to Chebyshev's theorem, at least
data lies within k standard deviation of mean.
For k = 2

Atleast 75% of data lies within two standard deviation for a non normal data.
Thus, atleast 75% of pregnancies last between 236 and 296 days approximately.
Answer:
41.04 meters
Step-by-step explanation:
The questions which involve calculating the angles and the sides of a triangle either require the sine rule or the cosine rule. In this question, the two sides that are given are adjacent to each other the given angle is the included angle. The initial position is given by A. The tree is denoted as C and the fence post is denoted as B. Since the use of sine rule will complicate the question, it will be easier to solve this question using the cosine rule. Therefore, cosine rule will be used to calculate the length of BC. The cosine rule is:
BC^2 = AB^2 + AC^2 - 2*AB*AC*cos(BAC).
The question specifies that AC = 70 meters, BAC = 25°, and AB = 35 meters. Plugging in the values:
BC^2 = 35^2 + 70^2 - 2(35)(70)*cos(25°).
Simplifying gives:
BC^2 = 1684.091844.
Taking square root on the both sides gives BC = 41.04 meters (rounded to two decimal places).
Therefore, the distance between the point on the tree to the point on the fence post is 41.04 meters!!!
I'm pretty sure the answer is A. hope that helped