Answer:
5 units
Step-by-step explanation:
An isosceles triangle is a triangle with two legs that have the same length. The perimeter of a triangle is the sum of the lengths of all sides of the triangle. Now taking this into account, we know that:
2L + B = 14 units
Where:
L is the measure of one leg
B is the measure of the base
Since two legs are the same and the base is 1 less, this means the measure of each leg would be:
B = L -1
Now we have two equations:
2L + B = 14 units
B = L- 1
We plug one equation into the other and make 1 equation:
2L + (L-1) = 14 units
Get rid of the parentheses:
2L + L - 1 = 14
Combine like terms:
3L - 1 = 14
Add 1 to both sides of the equation:
3L - 1 + 1 = 14 + 1
3L = 15
Divide both sides by 3:
3L/3 = 15/3
L = 5
So the length of a leg is 5 units
Let's check!
B = L - 1
B = 5 - 1
B = 4
Then we use that to solve for the perimeter:
2L + B
2(5) + 4
10 + 4 = 14
Answer:
The answer is No.
Step-by-step explanation:
The answer is no because an integer is any whole number that isn't a fraction. So this can be positive and still be an integer.
Answer:

Step-by-step explanation:
Changing Bases to Evaluate Logarithms

Apply change of base formula'

log term should be the numerator and denominator is the log base


64 is 4^3 and 16 is 4^2

Move the exponent before log

top and bottom has same log so cancel it out

<span>1st year value =45$
2nd year value=45+2.80$=47.80$
3rd year value=47.8+2.80$=50.60$
4th year value=50.60+2.80=53.40$
5th year value=53.40+2.80=56.20$
ater 5 years value of share becomes 56.20$
or
share after 5 years= 45+4*2.80=45+11.20=56.20$</span>
Answer:
No. See explanation below.
Step-by-step explanation:
Since the cards are being selected <u>without replacement,</u> every time we select a card, <u>the probability varies</u> (since there is one less card) and therefore, the probability doesn't remain the same for every trial and therefore, the probability of success changes for every trial.
It is because of this that this probability experiment doesn't represent a binomial experiment.