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2 years ago

Find the values for θ that make each statement true. a. sinθ=cos32 b. cosθ=sin(θ+20).

Mathematics

1 answer:

faltersainse [42]2 years ago

8 0

Answer:

a. 58

b. 35

Step-by-step explanation:

a. Given,

sinθ = cos 32

We know that cos x = sin (90 - x)

⇒ sin θ = sin (90 - 32)

⇒ sin θ = sin 58

⇒ θ = 58

Thus, the value of θ would be 58.

b. Given,

cosθ = sin(θ+20),

sin (90 - θ) = sin (θ + 20)

⇒ 90 - θ = θ + 20

⇒ 90 - 20 = θ + θ

⇒ 70 = 2θ

⇒ θ = 35

Thus, the value of θ would be 35.

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What is the answer need it

denis-greek [22]

Answer:

$\frac{7}{10} |$

Step-by-step explanation:

STEP 1:

2/3 + 7/10 = ?

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(2/3, 7/10) = 30

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

$(\frac{2}{3}$ * $\frac{10}{10})$ + $(\frac{7}{10} * \frac{3}{3})$ = ?

Complete the multiplication and the equation becomes

$\frac{20}{30} + \frac{21}{30}$

The two fractions now have like denominators so you can add the numerators.

Then:

$\frac{20+21}{30} = \frac{41}{30}$

This fraction cannot be reduced.

The fraction 41/30

is the same as

41 divided by 30

Convert to a mixed number using

long division for 41 ÷ 30 = 1R11, so

41/30 = 1 11/30

Therefore:

2/3+7/10= 1 11/30

STEP 2:

41/30 + -2/3

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(41/30, -2/3) = 30

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

$(\frac{41}{30} *\frac{1}{1} ) + ( \frac{-2}{3} * \frac{10}{10} )$