Question

What is the factorization of the trinomial below 4x2+28x+48

Answer 1

Answer:

$4x^2 + 28x +48 = 4(x+4)(x+3)$

Step-by-step explanation:

We are given the following information in the equation:

$4x^2 + 28x +48$

We have to factorize the given expression.

We will use the technique of splitting the middle term to factorize.

Factorization can be done in the following manner:

$4x^2 + 28x +48\\\Rightarrow 4(x^2 + 7x + 12)\\\Rightarrow 4(x^2 + 4x + 3x + 12)\\\Rightarrow 4[x(x+4)+3(x+4)]\\\Rightarrow 4(x+3)(x+4)$

Hence, the given expression can be factorized as:

$4x^2 + 28x +48 = 4(x+4)(x+3)$

Answer 2

Answer:

4(x +3)(x +4)

Step-by-step explanation:

First of all, recognize that each coefficient is a multiple of 4.

Factoring that out makes it easier to see that you need factors of 12 that add to give 7. Those are not hard to find as being 3 and 4. These numbers go into the binomial factors to give ...

... 4x^2 +28x +48 = 4(x^2 +7x +12) = 4(x +3)(x +4)