Answer:
20kg of $0.89 candy
10kg of $1.10 candy
Step-by-step explanation:
Candy 1 = 0.89 per kg
Candy 2 = 1.10 per kg
Total kilogram, kg = 30
Let candy 1 = x ; candy 2 = (30 - x) ;
0.89x + 1.10(30 - x) = 0.96(30)
0.89x + 33 - 1.10x = 28.8
0.89x - 1.10x = 28.8 - 33
-0.21x = - 4.2
x = 4.2 / 0.21
x = 20
20kg of $0.89 candy
(30 - x) = (30 - 20) = 10kg
10kg of $1.10 candy
Answer:
if the line keeps going and theynever touch
Step-by-step explanation:
X=60
That’s the answer
What I did to get it
(3x-60)=120
+60. +60
3x =180
————. = 60
3
X=60
The average score of all the students in both classes is 84.
<h3>How to calculate the average?</h3>
The class with 30 students had an average score of 80 on a test. The total score will be:
= 30 × 80
= 2400
A class with 20 students had an average score of 90 on the same test. The total score will be:
= 20 × 90
= 1800
Total scores = 2400 + 1800 = 4200
Number of students = 20 + 30 = 50
The average score will be:
= Total score / Total students
= 4200 / 50
= 84
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Answer: The required scale factor of the dilation is 4.
Step-by-step explanation: Given that the parallelogram FGHJ was dilated and translated to form similar parallelogram F'G'H'J'.
We are to find the scale factor of the dilation.
From the graph, we note that
JH = 2 units and J'H' = 8 units.
We know that
Therefore, the scale factor of the given dilation is
Thus, the required scale factor of the dilation is 4.
