Answer:
i = 45% and ii = 47% (Rounded)
Step-by-step explanation:
Simply divide 27 by 60 to get i:
27/60=.45
Convert to a percent chance.
.45=45%
Then divide 395 by 840 to get ii:
395/840=.47
Convert to a percent chance.
.47=47%
Since there are 300 students you have to use proportions to solve the percents. First for strawberry you need to set up a proportion such as x/300=30/100 to show you are trying to find 30%of 300. Then you must cross multiply so 300 times 30 and 100 times x. Then you have 9,000 and 100, so you divide 9,000 by 100 and then you get 90 which is the portion of kids who liked strawberry flavored ice cream. You should do the exact same thing for vanilla ice cream like this: x/300=29/100 but since you’re finding 29% you need to put a 29 over 100. Then you cross multiply and do 300 times 29 and do x times 100. Which makes you get 8,700 and 100, and then you divide 8,700 by 100 and get 87 for vanilla ice cream. Lastly you need to subtract 87 from 90 since it asked how many more students liked strawberry than vanilla: 90-87=
Can you please mark branliest? Thank you!
Answer:
Here we have the function:
S(t) = 500 - 400*t^(-1)
Then the rate of change at the value t, will be:
S'(t) = dS(t)/dt
This differentiation will be:
S'(t) = -400/t^2
Then:
a) the rate of change at t = 1 is:
S'(1) = -400/1^2 = -400
The rate of change after one year is -400
b) t = 10
S'(10) = -400/10^2 = -400/100 = -4
The rate of change after 10 years is -4, it reduced as the years passed, as expected.
The answer to this is 35 because i did caculation and thats the answer it gave me
