Answer:
9.42 cubic inches
Step-by-step explanation:
In order to find the volume for a sphere, we use the formula V = πr. For the sake of simplicity, we will be using 3.14 for π. Before we plug anything in, let's get our radius. Remember, the radius is half of the diameter.
Equation: d = 2r
Replace: 6 = 2r
Divide: 3 = r
Now that we have our radius, let's plug in what we have and solve.
Equation: V = 3.14r
Replace: V = 3.14(3)
Multiply: V = 9.42
Remember, volume is measured in cubic units, so use cubic inches for the unit here.
Answer:
Step-by-step explanation:
The greatest common favor is 5
Given 4 boxes of pencils cost $5,
Unknown- slope
$1.25 per box since $5/boxes
Equation y=mx+b
Substitute $1.25/per box for m
Solve y=$1.25x
The Check
$5=$1.25/per box(4 boxes)
$5=$5
Answer:
90 in²
Step-by-step explanation:
The figure's area is that of four right triangles, each with legs of 6 in and 7.5 in. The area of each triangle is half the product of the leg lengths, so is ...
triangle area = (1/2)(6 in)(7.5 in)
Then the area of 4 of those triangles is ...
figure area = 4 · triangle area = 2(6 in)(7.5 in) = 90 in²
Answer:
Claim 2
Step-by-step explanation:
The Inscribed Angle Theorem* tells you ...
... ∠RPQ = 1/2·∠ROQ
The multiplication property of equality tells you that multiplying both sides of this equation by 2 does not change the equality relationship.
... 2·∠RPQ = ∠ROQ
The symmetric property of equality says you can rearrange this to ...
... ∠ROQ = 2·∠RPQ . . . . the measure of ∠ROQ is twice the measure of ∠RPQ
_____
* You can prove the Inscribed Angle Theorem by drawing diameter POX and considering the relationship of angles XOQ and OPQ. The same consideration should be applied to angles XOR and OPR. In each case, you find the former is twice the latter, so the sum of angles XOR and XOQ will be twice the sum of angles OPR and OPQ. That is, angle ROQ is twice angle RPQ.
You can get to the required relationship by considering the sum of angles in a triangle and the sum of linear angles. As a shortcut, you can use the fact that an external angle is the sum of opposite internal angles of a triangle. Of course, triangles OPQ and OPR are both isosceles.
