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Ket [755]
3 years ago
15

Find the measure of an isosceles obtuse triangle with one angle that is 32 degrees.

Mathematics
1 answer:
stich3 [128]3 years ago
5 0

Answer:

The measure of angles of the triangle are 32,32 and 116.

Step-by-step explanation:

It is given that the triangle is an isosceles obtuse triangle with one angle that is 32 degrees.

An angle whose measure is more than 90 degree is called obtuse angle.

It means measure of one angle is more than 90 degree and two tangle are same acute angles.

Measure of one angle is given which is an acute angle (less than 90 degree).

Therefore the measure second angle is als 32.

According to angle sum property the sum all three angle of a triangle is 180 degree.

180-32-32=116

Therefore the measure of third angle is 116 degree.

To use Law of Sine and Cosine, we need at least one side. Since no side given, therefore we can not find the sides.

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If a sprinkler waters 1/15 of a lawn in 1/3 hour, how much time will it take to water the entire lawn?
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Answer:

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Hope This Helps!!!

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The coordinates of the midpoint of
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2. A parallelogram must be a rhombus when its (2 pts)
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21. Paul has $900 to invest in a savings account that has an annual interest rate of 1.8%, and a money market account that pays
Iteru [2.4K]

The polynomial that gives the interest earned after a year will have variables, exponents and constants that are joined by operators.

  • The interest earned after one year is <u>0.018·x</u>

Reasons:

The amount Paul has to invest = $900

The annual interest rate from the savings account = 1.8%

The amount the money market account pays per year = 4.2 %

Required: The polynomial for the interest Paul earned by investing <em>x</em> dollars in the savings account.

Solution:

The interest earned is found using the compound interest formula as follows;

\displaystyle A = \mathbf{P \cdot \left(1 + \frac{r}{n} \right)^{n \cdot t}}

Where;

A = The amount in the account after one year

P = The original amount invested = x

r = The interest rate offered on the investment = 1.8% = 0.018

t = The time of the investment = 1 year

n = The number of times of application of the interest per period = Once per year

Which gives;

Interest = Amount earned = A - P

Therefore;

\displaystyle Interest, \ I  = \mathbf{P \cdot \left(1 + \frac{r}{n} \right)^{n \cdot t} - P}

Plugging in the values gives;

\displaystyle I  = x \cdot \left(1 + \frac{0.018}{1} \right)^{1 \times 1} - x = x \cdot 1.018^1 - x = 1.018 \cdot x - x = 0.018 \cdot x

The polynomial equation is therefore;

Interest, I = 0.018·x

Using the simple interest formula, we have;

\displaystyle Interest = \mathbf{\frac{P \times r \times t}{100}}

Which gives;

\displaystyle Interest = \frac{x \times 1.8 \times 1}{100}  = 0.018 \cdot x

Interest earned by investing in the savings account for one year, I = 0.018·x

  • The polynomial representing the interest earned is <u><em>I</em></u><u> = 0.018·x</u>

Learn more here:

brainly.com/question/11314161

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