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3 years ago

-4w+18w+2=10-6w What is w?

Mathematics

2 answers:

Vlada [557]3 years ago

5 0

Answer:

2/5 or 0.4

Step-by-step explanation:

- 4w + 18w + 2 = 10 - 6w

14w + 2 = 10 - 6w

14w + 6w + 2 = 10

20w + 2 = 10

20w = 10 - 2

20w = 8

w = 8/20

w = 2/5

Check:

-4(0.4) + 18(0.4) + 2 = 10 - 6(0.4)

7.6 = 7.6 correct

Cerrena [4.2K]3 years ago

3 0

Answer:

w = 2/5 or 0.4.

Step-by-step explanation:

-4w+18w+2=10-6w Add 6w to both sides:

-4w + 18w + 6w + 2 = 10 Subtract 2 from both sides:

-4w + 18w + 6w = 10 - 2

20w = 8

w = 8/20

w = 2/5.

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Drupady [299]

Answer:

a. $\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c$

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Step-by-step explanation:

a. The volume of water initially in the fish tank = 15 liters

The volume of brine added per minute = 5 liters per minute

The rate at which the mixture is drained = 5 liters per minute

The amount of salt in the fish tank after t minutes = x

Where the volume of water with x grams of salt = 15 liters

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$\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c$

b. The amount of salt, x after t minutes is given by the relation

$\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c$

$dx = 6\frac{2}{3} \cdot c \cdot dt$

$x(t) = \int\limits \, dx = \int\limits \left ( 6\frac{2}{3} \cdot c \right) \cdot dt$

$x(t) = 6\frac{2}{3} \cdot c \cdot t$

c. Given that in 10 minutes, the amount of salt in the tank = 25 grams, and the volume is 15 liters, we have;

$x(10) = 25 \ grams(15 \ in \ liters) = 6\frac{2}{3} \times c \times 10$

$6\frac{2}{3} \times c =\dfrac{25 \ grams }{10}$

$c =\dfrac{25 \ g/L }{10 \times 6\frac{2}{3} } = \dfrac{25 \ g/L}{10 \times \dfrac{20}{3} } =\dfrac{3}{200} \times 25 \ g/L= \dfrac{75}{200} \ g/L = \dfrac{3}{8} \ g/L$

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As the weather changes from Summer to Fall, it was noted that the temperature dropped 20°F over 4 weeks. It continued to drop th

mihalych1998 [28]

Answer:

The integer that represents the change in the temperature each week = 5

The temperature of the weather drops 5°F each week

Step-by-step explanation:

The given parameters regarding the weather are;

The range over which the temperature dropped = 20°F

The duration over which the temperature dropped = 4 weeks

The rate at which the weather dropped each week = The same amount (constant rate)

Therefore, we have;

For a constant rate of change, the rate of change of the temperature of the weather, m, is given as follows;

m = (The change in the temperature)/(The duration of the change)

m = 20°F/(4 weeks) = 5°F/week

The integer that represents the change in the temperature each week = 5

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3 years ago