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3 years ago

Morgan needed to write an equation.Explain whether she actually wrote an equation 3X5?

Mathematics

1 answer:

Mice21 [21]3 years ago

5 0

It's not an equation because there's no answer to the problem.

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using compound interest, how long does it take to double a 1000 dollar investment that pays 6.5% annual interest, compounded mon

KonstantinChe [14]

Answer:

11 years approx

Step-by-step explanation:

Given data

P=$1000

A=2000

R=6.5%

T= ?

Calculate time, solve for t

t = ln(A/P) / r

substitute

t=ln(2000/1000)/0.065

t=ln(2)/0.065

t=0.693/0.065

t=10.66

Hence the time is 11 years approx

3 0

3 years ago

Use the number line below, where RS = 7y +5. ST = 3y +5, and RT = 70. a. What is the value of y?

NeTakaya

Answer:

Step-by-step explanation:

7y+5+3y+5=70

10y+10=70

10y=60

y=6

7(6)+5= 42+5= 47

3(6)+5= 18 + 5 =23

47+23= 70

8 0

3 years ago

You invest an initial $1,000 in an account that has an annual interest rate of 2%, compounded quarterly. how much money will you

kiruha [24]

Check the attached file for the answer.

8 0

2 years ago

Which bacteria sample (A or B) had a smaller initial population? What was that value?

zubka84 [21]

Answer:

B has a smaller initial population of 500

Step-by-step explanation:

Given

See attachment for complete question

Required

The bacteria with the smaller initial population

The initial population is at x = 0

For bacteria A;

$A(x) = 600$ when $x = 0$

For bacteria B, we have:

$B(x) = 500(2)^x$

Substitute 0 for x

$B(x) = 500(2)^0$

$B(x) = 500*1$

$B(x) = 500$

So; when x = 0

$A(x) = 600$ and $B(x) = 500$

Because; 500 < 600

We can conclude that B has a smaller initial population of 500

4 0

2 years ago

What is the inverse and restricted domain of the equation 8x^2-3

kari74 [83]

Answer: $\bold{y=\pm \dfrac{\sqrt{2(x+3)}}{4},\qquad x\neq -3}$

Step-by-step explanation:

y = 8x² - 3 (Restriction: none - x is All Real Numbers)

The inverse is when you swap the x's and y's and then solve for y

x = 8y² - 3 swapped the x and y

x + 3 = 8y² added 3 to both sides

$\dfrac{x+3}{8}=y^2$ divided both sides by 8

$\sqrt{\dfrac{x+3}{8}}=\sqrt{y^2}$ square rooted both sides

$\pm \sqrt{\dfrac{x+3}{8}}=y$ simplified

$\pm \sqrt{\dfrac{x+3}{8}\bigg(\dfrac{2}{2}\bigg)}=y$ rationalized the denominator

$\pm \sqrt{\dfrac{2(x+3)}{16}}=y$ simplified

$\pm \dfrac{\sqrt{2(x+3)}}{4}=y$ simplified

Restriction:

The radical (inside the square root sign) cannot be negative

→ 2(x + 3) ≥ 0

x + 3 ≥ 0 divided both sides by 2

x ≥ -3 subtracted 3 from both sides

4 0

3 years ago