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guajiro [1.7K]
3 years ago
10

Help will mark!!

Biology
1 answer:
Nookie1986 [14]3 years ago
5 0
<span>beneficial DNA mutations.


</span>
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Difference between mycoplasma and l form bacteria​
Snezhnost [94]

Answer:

L-form bacteria are distinct from mycoplasmas, because Mycoplasma spp. do not originate from bacteria that normally possess a cell wall. ... Some of these bacteria remain as CWDB (stable L-forms), whereas others revert back to possession of a cell wall (unstable L-forms).

Explanation:

5 0
3 years ago
Kevin is studying predator-prey interactions. One day he notices a spider eating a cricket caught in its web. Later that day, a
s344n2d4d5 [400]

Answer:

The correct answer is option - A. 0.

Explanation:

Producers are the organism that produces on their own. They do not depend on other organisms for their nutrition and energy such as green plants. They transfer energy and nutrition.

In the given scenario there is no producer present all are consumers of different levels. Cricket is a primary consumer, a spider is a secondary consumer and bird is the third consumer in this food chain.

Thus, the correct answer is option- A. 0.

4 0
3 years ago
How many atp equivalents are consumed in the conversion of each of the following to a glucosyl residue in glycogen?
Nina [5.8K]
<h3><u>Answer;</u></h3>

Dihydroxyacetone phosphate - 1

Fructose-1,6-bisphosphate - 1

Pyruvate - 13

G-6-P - 1

<h3><u>Explanation;</u></h3>

1) Dihydroxyacetone phosphate = 1

G1P + GTP --> UDPG + PPi two P is equivalent to 2 ATP --->2 ADP + Pi) Therefore, two ATP equivalents - but UDP is the product and only one P needed

2 DHAP --> F1,6-BP -->F6P --> G6P -->G1P -->UDPG --> glucosyl residue

2) Fructose 1,6-bisphosphate = 1

3) Pyruvate = 13

2 pyr + 2 ATP --> 2 OAA

2 OAA + 2 GTP --> 2 PEP

2 PEP --> 2 2PG --> 2 3PG

2 3PG + 2 ATP --> 2 1,3 BPG

2 1,3 BPG + 2 NADH --> 2 G3P

2 NADH = 6 ATP

2 G3P --> DHP + G3P --> FDP -- > F6P + P

F6P --> G6P --> G1P

G1P + UTP --> UDPG + PP

4) Glucose-6-phosphate = 1

G6P -->G1P G1P + UTP --> UDP-GLC + 2 Pi

UDP-Glc + glycogen --> glycogen+ 1 Glc

4 0
3 years ago
30 points
MA_775_DIABLO [31]
I'm working on the assignment rn. But here are some clues to help you.

8 0
3 years ago
Please help or I’ll get a bad grade.
Viefleur [7K]

Answer:

b

Explanation:

8 0
4 years ago
Read 2 more answers
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