To find the answer to this question, we need to plug in x=10 into the equation y = -63x + 825.
y = -63(10) + 825
y = -630 + 825
y = 195
Thus, there will be 195 cans left after 10 days.
<u>Solution</u><u>:</u>


- Now, square root and square gets cancel out in the LHS. And in the RHS, apply the identity: (a + b)² = a² + 2ab + b².

- Now, transpose 4x and 4 to LHS.

- Now, do the addition and subtraction.

<u>Answer</u><u>:</u>
<u>x </u><u>=</u><u> </u><u>±</u><u> </u><u>3</u>
Hope you could understand.
If you have any query, feel free to ask.
Answer:
Step-by-step explanation:
the temperature went down it became colder
it went down 8