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zvonat [6]
3 years ago
12

For the following system, use the second equation to make a substitution for y in the first equation. 2x + y = 5 y + 3 = 2x

Mathematics
2 answers:
deff fn [24]3 years ago
7 0
For the second equation, y=2x-3. Substituting this in, you get 2x+2x-3=5. Add the 2x's (4x), and add 3 to the 5 (8). You should get 4x=8, which will give you x=2.  
Alla [95]3 years ago
6 0
If y equals 2x - 3 in the second equation, than subsitute it in for y in the first.
2x + 2x - 3 = 5
4x - 3 = 5
4x = 8
x=2
2(2) + y = 5
x = 2 and y = 1

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Write the equation of line in slope-intercept form, which is parallel to y=−2x+5 and passing through the point (1, −4).
sweet-ann [11.9K]

Answer:

Step-by-step explanation:

y=−2x+5

m= -2

As required line is parallel to y=−2x+5, slope will be same for these two lines.

slope of required line = -2

m = - 2 ; (1, -4)

y - y₁ = m (x - x₁)

y - (-4) = -2 * (x - 1)

y + 4 = -2x + 2

2x - 2 + y +4= 0

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6 0
3 years ago
Explain whether or not the plant labeled p(x)=x2+x+3 has any rational or irrational roots.
olasank [31]

frational roots are those numbers that can be written in form \frac{a}{b} where a and b are integers (integers are like -5,-4,-3,-2,-1,0,1,2,3,4, etc)

some examples are 1=1/1, 2=2/2, -4=-4/1, 4/3, 0.111111111111=1/9, etc

irrational numbers are numbers that can't be written that way like pi

numbers that involve √-1 or a square root of any negative number are called complex numbers and are neither rational nor irrational.


roots are the values of x that makes the function equal to 0


p(x)=x^2+x+3

set equal to 0

0=x^2+x+3

I can't factor so use quadratic formula

for 0=ax^2+bx+c

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

so

x=\frac{-1 \pm \sqrt{1^2-4(1)(3)}}{2(1)}

x=\frac{-1 \pm \sqrt{-11}}{2}

√-11 is a square root of a negative number so it is a complex number. therefore, the function does not have rational or irrational roots


p(x) has no rational or irrational roots

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