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8_murik_8 [283]
3 years ago
5

Need help, show work on a piece of paperon problem 8

Mathematics
1 answer:
docker41 [41]3 years ago
6 0
<h3>Given</h3>
  • ∠AOB = ∠COD = x² -2
  • ∠BOC = 2x -10
  • ∠AOD = ∠AOB + ∠BOC + ∠COD = 16x +2
<h3>Find</h3>
  • x
  • the measures of the angles
<h3>Solution</h3>

Substituting the given values of the angles into the given relaion, we get ...

... (x² -2) + (2x -10) + (x² -2) = 16x +2

... 2x^2 -14x -16 = 0 . . . . . subtract the right side (16x+2)

... 2(x +1)(x -8) = 0 . . . . . . .factor

Values of x that satisfy this equation are ...

... x = -1, x = 8

The value x = -1 does not give rise to positive angle values.

For x = 8, the angles are ...

... ∠AOB = ∠COD = 8²-2 = 62

... ∠BOC = 2·8 -10 = 6

... ∠AOD = 16·8 +2 = 130 . . . . = 62 +6 +62

The answer to the question not asked is ...

... x = 8; ∠AOB = ∠COD = 62; ∠BOC = 6; ∠AOD = 130

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