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Minchanka [31]
2 years ago
14

2 FOR 2.20 UNIT RATE

Mathematics
1 answer:
dlinn [17]2 years ago
5 0

Answer: (if your asking for the unit rate of that)

the unit rate is 1.10

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From the sample space S​={1,2,3,4,...,15} a single number is to be selected at random. Given the following​ events, find the ind
marshall27 [118]

The probabilities of the given events are:

A. P(even) = P(A) = 7/15

B. P(multiple) = P(B) = 3/15

C. P(prime) = 6/15

D. P(B|A) = 3/7

<h3>What is probability?</h3>

Probability is defined as the ratio of the number of favorable outcomes of an event to the total number of possible outcomes.

P(E) = n(E)/n(S)

<h3>Calculation:</h3>

The given sample space is S = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15}

So, n(S) = 15

A. The selected number is even:

Consider the event as A.

The set of even numbers in the given sample is {2,4,6,8,10,12,14}

So, n(A) = 7

Then, the required probability is

P(A) = n(A)/n(S)

       = 7/15

B. The selected number is a multiple of 4:

Consider the event as B.

The set of multiples of 4 in the given sample is {4,8,12}

So, n(B) = 3

Then, the required probability is

P(B) = n(B)/n(S)

       = 3/15

C. The selected number is prime:

Consider the event as C.

The set of prime numbers in the given sample is {2,3,5,7,11,13}

So, n(C) = 6

Then, the required probability is

P(C) = n(C)/n(S)

       = 6/15

D. calculate P(B|A):

Since events B and A are dependent events of the same sample,

n(A∩B) = 3 and the set is {4,8,12}. Then, P(B|A) is

P(B|A) = n(A∩B)/n(A)

⇒ P(B|A) = 3/7

Learn more about the probabilities here:

brainly.com/question/251701

#SPJ1

7 0
2 years ago
4. A school has a toy drive for a holiday in which students bring in toys to be donated to
sergejj [24]
<h3>Its greater for junior: Juniors=40+25+5+20+40–>140 Seniors=5+35+45+30+15—>130  It’s greater for junior because they have 10 more toys than seniors</h3>
7 0
4 years ago
Can you please help me
nika2105 [10]
I believe it’s 0.5 :)
4 0
3 years ago
Read 2 more answers
Please help!!
enot [183]

Since g(h(x))=h(g(x))= x, hence functions h and g are inverses of each other

Given the functions expressed as:

h(x) =\sqrt{2x+2}\\g(x)\frac{x^2-2}{2}  \\

In order to check whether they are inverses of each other, we need to show that h(g(x)) = g(h(x))

Get the composite function h(g(x))

h(g(x))=h(\frac{x^2-2}{2} )\\h(g(x))=\sqrt{2(\frac{x^2-2}{2} )+2}\\h(g(x))=\sqrt{x^2-2+2} \\h(g(x))=\sqrt{x^2}\\h(g(x))=x

Get the composite function g(h(x))

g(h(x))=\frac{(\sqrt{2x+2} )^2-2}{2} \\g(h(x))=\frac{2x+2-2}{2}\\g(h(x))=\frac{2x}{2}\\g(h(x))=x

Since g(h(x))=h(g(x))= x, hence functions h and g are inverses of each other

Learn more on inverse functions here; brainly.com/question/14391067

7 0
3 years ago
Read 2 more answers
Which operation should be performed<br> first to solve the inequality below?<br> -3x + 5 = 23
Ne4ueva [31]

Answer:

Pass the number 5 to the other side with te opposite sign in order to leave the x alone

it would be

-3x = 23-5

Then you divide by -3 and thats ur answer

4 0
4 years ago
Read 2 more answers
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