Hi there! hopefully this helps!
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Question: "<em>Which statement compares the Autofill and Flash Fill features?</em>"
Answer: "Only the Flash Fill feature can <u>combine data</u> from other cells."
(<em>The </em><u><em>second</em></u><em> answer choice</em>).
Answer:
The answer to this question can be given as:
Class definition:
public class Averager //define class Average.
{
private int sum = 0;
//define variable sum.
private int count = 0;
//define variable count.
public int getSum() //define function getSum().
{
return sum; //return value.
}
public void add(int x)
//define function add().
{
sum = sum + x; //calculate sum
count=count+1; //increase value of count.
}
public int add(int x)
//define function add().
{
return count; //return value.
}
public double getAverage() //define function getAverage().
{
return (double)sum/count; //return value
}
}
Explanation:
The above class definition can be described as:
- In the above class definition first we define a class that is " Averager". In this class we define two integer variable that is "sum and count" and assign a value that is 0. Then we define a functions :
- First we define getSum() function in this function we does not pass any value and the return type of this function is int that will return an integer value.
- Then we define add() function we use this function two times but both functions have different from each other.
- In first time implementation, we define this function and the return type of this function is void which means it does not return any value. In this function, we calculate the sum value and increase the value of the count variable by 1.
- In second time implementation, we define this function and the return type of this function is int which means it will return a value. In this function, we will return the count variable value.
- At the last, we define a getAverage() that calculates the average of the added values in the sum variable and returns its value.
BASIC
(Beginners' All-purpose Symbolic Instruction Code)
Answer:
5/ 18
Explanation:
Given :
List A: [20,10,20]
List B: [40,10,30,20,40,30]
Chance that number drawn from list A is larger than or equal to that drawn dlfrom list B.
If:
A = 20
B ≤ 20 : [10,20] = 2
A = 10
B ≤ 10 : [10] = 1
A = 20
B ≤ 20 : [10,20] = 2
Probability = Required outcome / Total possible outcomes
Hence,
required outcome = (2 + 2 +1) = 5
Total possible outcomes = 3C1 * 6C1 = (3 * 6) = 18
Hence,
chance that the number we drew from list A is larger than or equal to the number we drew from list B
= 5 / 18
Answer: This element needs 3 electrons to complete its octet state
Why?:
since the electrons in 2s2 are already paired they cannot form a bond pair with electrons from other elements without hybridisation however the 3 electrons in 2p3 are unpaired so can form bond pairs with electrons from other elements without hybridisation.
Hope this helps!
