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r-ruslan [8.4K]
3 years ago
15

Explain! Prize! Thank you!!!!

Mathematics
2 answers:
aksik [14]3 years ago
8 0
It’s (d) since the ration is 6/15 if u simplify that it will give u 2/5 I hope this helps
andrew11 [14]3 years ago
6 0

Answer:

b

Step-by-step explanation:

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Solve the equation using the distributive property and properties of equality. -5(a+3)=-55 What is the value of a? A.)-14 B.) -8
Colt1911 [192]

Answer:

C) 8

Step-by-step explanation:

-5(a+3)=-55

a+3=-55/-5

a+3=11

a=11-3

a=8

4 0
3 years ago
Let the universal set be the set of integers and let A = {x | x^2 ≤ 5}. Write A using the roster method.
Zarrin [17]

Answer:

Step-by-step explanation:

Given that Z the set of integers is the universal set and

A is given in set builder form.

A = {x | x^2 ≤ 5}

To convert this into roster form, we can find solutions for x

When x^2\leq 5\\|x|\leq \sqrt{5} =2.236

i.e. all integers lying between -2.236 and 2.236

The only integers satisfying this conditions are

-2,-1,0,1,2

Hence A in roster form is

A={-2,-1,0,1,2}

8 0
3 years ago
The scatter plot shows data collected on the number of students who get off the bus at the first and the last stop of various sc
icang [17]

Answer:

d

Step-by-step explanation:

7 0
3 years ago
single die is rolled twice. Find the probability of rolling an oddodd number the first time and a number greater than 33 the sec
givi [52]

Answer:

\frac{1}{4}

Step-by-step explanation:

A single die is rolled twice, we have to find the probability of rolling an odd number in first throw and a number greater than 3 in the second throw.

a) Rolling an Odd number in first throw

A die has total 6 possible outcomes, out of which 3 are odd numbers i.e. 1,3 and 5

So, total number of possible outcomes = 6

Total Favorable outcomes (Odd numbers) = 3

Probability is defined as the ratio of favorable outcomes to total number of outcomes. So,

The probability of rolling an odd number would be = \frac{3}{6} = \frac{1}{2}

b) Rolling a number greater than 3 in second throw

Here again total possible outcomes = 6

Favorable outcomes (Numbers greater than 3 are 4, 5 and 6) = 3

So,

The probability of rolling a number greater than 3 =  \frac{3}{6} = \frac{1}{2}

These two events(rolls) are independent of each other, so the overall probability of both events occurring would be the product of individual probabilities.

So,

Probability of rolling an odd number the first time and a number greater than 3 the second time = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4}

6 0
3 years ago
El has $10.25 to spend at
Nonamiya [84]
No . but she can buy 2 of the books but not all 3
5 0
3 years ago
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