Answer:
zeros : -3/2 , multiplicity = 1
1 , multiplicity = 2
Step-by-step explanation:
To find zeros we set each factor =0 and solve for x
2x+3 =0
subtract 3 on both sides
2x= -3
divide by 2 on both sides
x= -3/2
The exponent of (2x+3) is 1 so multiplicity =1
Now we set (x-1)^2 =0
take square root on both sides
x-1 =0
add 1 on both sides
x=1
For (x-1)^2 the exponent is 2
So multiplicity = 2
The vertex of the graph is at (5, (6 + 2)/2) = (5, 4)
The equation of a quadratic graph is given by y - k = 4p(x - h)^2, where (h, k) is the vertex, p is the distance from the vertex to the focus.
Here, (h, k) = (5, 4) and p = 6 - 2 = 2 and since the focus is on top of the directrix, the parabola is facing up and the value of p is positive.
Therefore, the required equation is y - 4 = 4(2)(x - 5)^2
y - 4 = 8(x^2 - 10x + 25)
y - 4 = 8x^2 - 80x + 200
y = 8x^2 - 80x + 204
Answer:
y = 2x - 1 is the required equation
Step-by-step explanation:
slope(m) = (3-7)/(2-4)
m = -4/(-2)
so, m = 2
Now,
y = mx + b
or, y = 2x + b
so, 3 = 2*2 + b
or, 3 = 4 + b
so, b = -1
equation would be y = 2x - 1
<span>73° , acute you would add 36 and 71 together and then subtract 180 and you would get your answer
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