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3 years ago

Estimates show that there are 1.410^8 pet fish and 9.410^6 pet reptiles in the United States.

1 answer:

5 0

$\bf \stackrel{fish}{1.4\times 10^8}~~+~~\stackrel{reptiles}{9.4\times 10^6}
\\\\\\
\stackrel{fish}{140000000}~~+~~\stackrel{reptiles}{9400000}\implies 
\begin{array}{rrrrllll}
140000000\\
+9400000\\
\text{\textemdash\textemdash\textemdash\textemdash\textemdash}\\
149400000
\end{array}\implies 1.494\times 10^8$

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3 years ago

Diego's history teacher writes a test for the class with 26 questions. The test is worth 123 points and has two types of questio

maxonik [38]

Answer:

The number of essay questions on the test were 9

Step-by-step explanation:

Given as :

Total number of questions in a test = 26

Total points for the 26 questions = 123

The point for each multiple choice questions = 3

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Let The number of multiple choice questions = m

Let The number of essay questions = e

<u>Now, According to question</u>

Total number of questions in a test = number of multiple choice questions + number of essay questions

Or, m + e = 26 .....A

Again

Total points for the 26 questions = point for each multiple choice questions × number of multiple choice questions + point for each essay questions × number of essay questions

i.e 3 × m + 8 × e = 123

Or, 3 m + 8 e = 123 .......B

Solving the equation we get

8 × ( m + e ) - (3 m + 8 e) = 8 × 26 - 123

Or, 8 m + 8 e - 3 m - 8 e = 208 - 123

Or,(8 m - 3m) + (8 e - 8 e) = 85

Or, 5 m + 0 = 85

∴ m = $\dfrac{85}{5}$

i.e m = 17

So,The number of multiple choice questions = m = 17

Put the value of m into eq A

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Or, e = 26 - 17

i.e e = 9

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Hence, The number of essay questions on the test were 9 . Answer

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3 years ago

A grower believes that one in five of his citrus trees are infected with the citrus red mite. How large a sample should be taken

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Answer: 68

Step-by-step explanation:

Formula for sample size when prior estimate of population proportion (p) is available: $n=p(1-p)(\dfrac{z^*}{E})^2$

, where z*= critical-value.

E= Margin of error.

Let p be the population proportion of trees are infected with the citrus red mite.

As per given , we have

$p=\dfrac{1}{5}=0.2$

E= ± 0.08

The critical z-value corresponding to 90% confidence level = z*=1.645

Substitute all the values in the above formula , we get

Required sample size : $n=(0.2)(1-0.2)(\dfrac{(1.645)}{0.08})^2$

$\Rightarrow\ n=(0.2)(0.8)(20.5625)^2$

$\Rightarrow\ n=0.16(422.81640625)\\\\\Rightarrow\ n=67.650625\approx68$ [Rounded to next integer.]

Thus, the minimum sample size should be taken =68

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3 years ago

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3 years ago

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We have to rationalize the denominator:
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3 years ago

Read 2 more answers

Estimates show that there are 1.4*10^8 pet fish and 9.4*10^6 pet reptiles in the United States.

Estimates show that there are 1.410^8 pet fish and 9.410^6 pet reptiles in the United States.