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3 years ago

This is a side view of a roller coaster. (see attached image.)

Mathematics

1 answer:

andreyandreev [35.5K]3 years ago

7 0

Let every line = 1 unit:

Point C is located at (0,0)

Point D is located at (7, 12)

The slope is the change in Y over the change in X:

Slope = 12-0 / 7-0 = 12/7

The equation of the line from C to D using mx +b:

m = slope, which we already calculated as 12/7

To solve for b, replace m with 12/7 to get

y=12/7x +b

replace x with 0 ( from point C )

y = 12/7(0) +b

Replace y with 0 (also from point C)

0 = 12/7(0)+b

Solve for b:

b = 0

The equation becomes y= 12/7x

The Domain is the X values, which range from A to E, -12 to 13

Which is written as (-12,13) or -12≤x≤13

The range is the Y values, which range from A to D, 0 , 12

Which is written as (0,12) or 0≤y≤12

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Find the surface area plz

vladimir1956 [14]

Hi again! ;)

If we want to find the surface area of a cube, we need to find the area of one surface first, and then multiply that by 9, since there are 9 sides/surfaces on a cube.

Since each side of a square is the same, we first find the area of one surface:

9 × 9 = 81

Then, to find the surface area, we multiply 81 by 6:

81 × 6 = 486

The surface area is
$486 \: {in}^{2}$

7 0

2 years ago

Suppose 52% of the population has a college degree. If a random sample of size 563563 is selected, what is the probability that

amm1812

Answer:

The value is $P(| \^ p - p| < 0.05 ) = 0.9822$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.52$

The sample size is n = 563

Generally the population mean of the sampling distribution is mathematically represented as

$\mu_{x} = p = 0.52$

Generally the standard deviation of the sampling distribution is mathematically evaluated as

$\sigma = \sqrt{\frac{ p(1- p)}{n} }$

=> $\sigma = \sqrt{\frac{ 0.52 (1- 0.52 )}{563} }$

=> $\sigma = 0.02106$

Generally the probability that the proportion of persons with a college degree will differ from the population proportion by less than 5% is mathematically represented as

$P(| \^ p - p| < 0.05 ) = P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 ))$

Here $\^ p$ is the sample proportion of persons with a college degree.

$P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma } < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )$