Answer:
Use SAS to show that triangles PRQ and PRS are congruent.
Step-by-step explanation:
Since PR bisects angle QPS, angles QPR and SPR are congruent. By reflexive property of congruence, PR is congruent to itself. Since PQ is congruent to PS, we can use SAS to show that the two triangles are congruent. By CPCTC, QR is congruent to SR.
9514 1404 393
Answer:
9 square units
Step-by-step explanation:
Pick's theorem is a useful relationship in circumstances like these. It tells you the area is ...
A = i + b/2 - 1
where i is the number of interior points (8), and b is the number of points on the border (4).
The area of this figure is ...
A = 8 + 4/2 -1 = 9
The area of the polygon is 9 square units.
_____
You can also get there by realizing the bounding rectangle is 4 units square. From that, corner triangles are cut. CW from upper left, those triangles have (base, height) dimensions of (3, 2), (1, 3), (3, 1), and (1, 2). So, the total of their areas is (1/2)(6 +3 + 3 +2) = 7 square units. The shaded area is then 16-7 = 9 square units, same as above.
If x' & x" are the roots (or x intercepts) of a quadratic equation, then it could be written:
y= (x-x')(x-x")
Since -6 & +6 are the roots of the quadratic function, then it could be written
as follows y= (x+6)(x+6) ===> y= x²-36. So the answer is B
Answer: 7
Step-by-step explanation:
divide 63 by 9
yes it very much so is my friend
