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3 years ago

How many two digit numbers are divisible by either 3 or 5?

Mathematics

2 answers:

matrenka [14]3 years ago

4 0

There are 30 numbers that are divisible by 3 and 5.

I hope this helps c:

tankabanditka [31]3 years ago

4 0

They are the numbers divisible by 15
15, 30, 45, 60, 75, 90

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Please answer with steps shown. Thanks!

maks197457 [2]

Answer: q = 40

Step-by-step explanation:

Given the quadratic formula as

x = [-b +/-√(b^2 -4ac)]/2a

b = -14

a = 1

c = q

Difference d between the two roots.

d = [-b + √(b^2 -4ac)]/2a - [-b -√(b^2 -4ac)]/2a

d = 2√(b^2 -4ac)/2a

d = √(b^2 -4ac)/a

And d = 6

Substituting the values of a,b and c. We have;

6 = √[(-14^2) - (4×1×q)]

Square both sides

6^2 = 196 - 4q

4q = 196 - 36

q = 160/4

q = 40

The equation becomes

x^2 - 14x + 40 = 0

3 0

4 years ago

Renee is simplifying the expression (7) (StartFraction 13 over 29 EndFraction) (StartFraction 1 over 7 EndFraction). She recogni

dsp73

Answer:

The correct option is commutative property.

Step-by-step explanation:

The expression that Renee is simplifying is:

$(7)\cdot(\frac{13}{29})\cdot(\frac{1}{7})$

It is provided that, Renee recognizes that 7 and $\frac{1}{7}$ are reciprocals, so she would like to find their product before she multiplies by $\frac{13}{29}$ .

The associative property of multiplication states that:

$a\times b\times c=(a\times b)\times c=a\times (b\times c)$

The commutative property of multiplication states that:

$a\times b\times c=a\times c\times b=c\times a\times b$

The distributive property of multiplication states that:

$a\cdot (b+c)=a\cdot b+a\cdot c$

The identity property of multiplication states that:

$a\times 1=a\\b\times 1=b$

So, Renee should use the commutative property of multiplication to find the product of 7 and $\frac{1}{7}$ ,

$(7)\cdot(\frac{13}{29})\cdot(\frac{1}{7})=(7\times\frac{1}{7})\times\frac{13}{29}=\frac{13}{29}$

Thus, the correct option is commutative property.

5 0

3 years ago

Read 2 more answers

F(x) = 4/x-9<br> g(x)=4/x + 9<br> find f(g(x))

Alenkinab [10]

Hello,

$f(x)= \dfrac{4}{x-9} \\

g(x)= \dfrac{4}{x+9} \\

f(g(x))=f( \dfrac{4}{x+9} )\\

= \dfrac{4}{ \dfrac{4}{x+9}-9} \\

= \dfrac{4(x+9)}{4-9x-81} \\

=- \dfrac{4x+36}{77x+9x} 


$

6 0

3 years ago

Solve. for. c m=c-s

podryga [215]

Answer:

s-c= m c

Step-by-step explanation:

8 0

2 years ago

A scientist has saline solutions with concentrations of 4% and 14% . He wants to mix some of each solution to get 65 milliliters

Komok [63]

Let volume of 4% solution = x and of 14% be y

them x + y = 65........(1) also using the actual weights of salt:-

0.04x + 0.14y = 65*0.06 = 3.9

multiplying the above equation by -25 we have

-x - 3.5y = -97.5 adding this to equation (1)

--2.5y = -32.5
y= 13

and x = 65 - 13 = 52

so we need 13 mls of the 14%, and 52 mls of the 4% solution.

8 0

3 years ago