Someone please help me

You deposit $2000 into an account that pays 6% compounded monthly. a. How much money will you have in the account after 1 year?

Masteriza [31]

We have a deposit of $2000 into an account that pays 6% compounded monthly, after a year we will have:

$\begin{gathered} \text{account}_{\text{year}}=2000\cdot(1+\frac{6}{100})^{12} \\ \text{account}_{\text{year}}=4024.4 \end{gathered}$

The effective annual yield (EAY) will be:

$\text{EAY}=\frac{account_{year}}{2000}-1=\frac{4024.14}{2000}-1=1.0122$

The EAY is 101.22%

8 0

7 months ago

-5/3 is a root of f(x) = (3x + 5) (x2 - 6x + 9)2 = 0 True False

Alex_Xolod [135]

False...................

8 0

2 years ago

Read 2 more answers

Use the Chain Rule to find the indicated partial derivatives. z = x^4 + xy^3, x = uv^4 + w^3, y = u + ve^w Find : ∂z/∂u , ∂z/∂v

k0ka [10]

I'll use subscript notation for brevity, i.e. $\frac{\partial f}{\partial x}=f_x$ .

By the chain rule,

$z_u=z_xx_u+z_yy_u$

$z_v=z_xx_v+z_yy_v$

$z_w=z_xx_w+z_yy_w$

We have

$z=x^4+xy^3\implies\begin{cases}z_x=4x^3+y^3\\z_y=3xy^2\end{cases}$

and

$\begin{cases}x=uv^4+w^3\\y=u+ve^w\end{cases}\implies\begin{cases}x_u=v^4\\x_v=4uv^3\\x_w=3w^2\\y_u=1\\y_v=e^w\\y_w=ve^w\end{cases}$

When $u=1,v=1,w=0$ , we have

$\begin{cases}x(1,1,0)=1\\y(1,1,0)=2\end{cases}\implies\begin{cases}z_x(1,2)=12\\z_y(1,2)=12\end{cases}$

and the partial derivatives take on values of

$\begin{cases}x_u(1,1,0)=1\\x_v(1,1,0)=4\\x_w(1,1,0)=0\\y_u(1,1,0)=1\\y_v(1,1,0)=1\\y_w(1,1,0)=1\end{cases}$

So we end up with

$\boxed{\begin{cases}z_u(1,1,0)=24\\z_v(1,1,0)=60\\z_w(1,1,0)=12\end{cases}}$

3 0

2 years ago

Please HELP PAST DUE I NEED THE GRADE help!!!

ArbitrLikvidat [17]

Answer:

(A:) I created a scatter plot similar to the one i used for mine, this is for the first part of your question

(B:) Positive Association

Step-by-step explanation:

(B:) Why? Because as your x value increases so does your y and it shows this with the data as well.

I had a tough time with this until i actually read through what it was really asking so i hope this helps you

7 0

3 years ago

Chloe is painting on a stretched canvas that has an area of 108 square inches. The length of the canvas is 12 inches. The width

Stolb23 [73]

Answer: Width of canvas = 9 inches

Area left for painting after painting the border = 70 square inches.

Explanation :

Since we have given that

Area of painting = 108 square inches

Length of canvas = 12 inches

As we know that

$\text{Area of rectangle} = length\times breadth$

$108=12\times breadth\\\\\frac{108}{12}=breadth\\\\9=breadth$

So, breadth of canvas = 9 inches .

Now, Chloe paints a 1 inch wide blue border on the canvas.

$\text{So, remaining length left for painting after painting the border} = 9-1-1=9-2=7\text{ inches}$

$\text{ Remaining breadth left for painting after painting the border }= 12-1-1=12-2= 10\text{ inches}$

$\text{So , area of remaining portion }= length\times breadth \\\\ \text{ area of remaining portion }=7\times 10\\\\\text{ area of remaining portion }=70 \text{ square inches}$

Hence, remaining area = 70 square inches .

6 0

2 years ago