The horizontal value in a pair of coordinates: how far along the point is. The X Coordinate is always written first in an ordered pair of coordinates (x,y), such as (12,5). In this example, the value "12" is the X Coordinate. Also called "Abscissa"
Let <em>x</em> = 8.132132132...
Then 1000<em>x</em> = 8132.132132132...
Subtract <em>x</em> from 1000<em>x</em> to eliminate the fractional part:
1000<em>x</em> - <em>x</em> = 8132.132132132... - 8.132132132...
999<em>x</em> = 8132 - 8 = 8124
<em>x</em> = 8124/999 = 2708/333
Answer:
B
Step-by-step explanation:
Answer:
Step-by-step explanation:
Part A:
We have two equations in the given question:
y=8x and y=2x+2
Then these two equations will intersect at a point where y is same fro both the equations:
In equation y=8x we will exchange y with the other equation which is y=2x+2 then we would have 8x=2x+2..
Part B:
8x = 2x + 2. Take the integer values of x between −3 and 3
x= -3
8(-3)=2(-3)+2
-24=-6+2
-24= -4
It is false
Now plug x= -2
8(-2)=2(-2)+2
-16 = -4+2
-16 = -2
This is false
Now plug x= -1
8(-1)=2(-1)+2
-8 = -2+2
-8=0
It is false
Now plug x= 0
8(0)=2(0)+2
0=0+2
0=2
It is false
Now plug x= 1
8(1)=2(1)+2
8=2+2
8=4
False
Now plug x= 2
8(2)=2(2)+2
16=4+2
16=6
False
Now plug x=3
8(3)=2(3)+2
24=6+2
24=8
It is false
It means there is no solution to 8x=2x+2 for the integers values of x between −3 and 3
Part C:
Plot the two given functions on a coordinate plane and identifying the point of intersection(values of the variables which satisfy both equations at a particular point) of the two graphs.
The graph is attached. The point of intersection at x =0.333 and value of y = 2.667....
. These vectors are not equal, then T doesn't satisfy the condition of scalar multiplication (homogeneity).
. Because these vectors are not equal, T doesn't satisfy the property of vector addition (additivity).
so T is not homogeneous.
then T is not additive.
then T is not additive.
