f(x) = 5x²
f(10) = 5(10)² = 5(100) = 500
f'(x) = 10x
f'(10) = 10(10) = 100
Now, find the line that passes through (10, 500) and has a slope of 100
y - y₁ = m(x - x₁)
y - 500 = 100(x - 10)
y - 500 = 100x - 1000
y = 100x - 500
Answer:
The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.
Step-by-step explanation:
Volume of the Cylinder=400 cm³
Volume of a Cylinder=πr²h
Therefore: πr²h=400

Total Surface Area of a Cylinder=2πr²+2πrh
Cost of the materials for the Top and Bottom=0.06 cents per square centimeter
Cost of the materials for the sides=0.03 cents per square centimeter
Cost of the Cylinder=0.06(2πr²)+0.03(2πrh)
C=0.12πr²+0.06πrh
Recall: 
Therefore:



The minimum cost occurs when the derivative of the Cost =0.






r=3.17 cm
Recall that:


h=12.67cm
The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.
Ignore bottom one please brainiest. edit: add cubed after the second bracket
Answer:
3:4 and 15:20
Step-by-step explanation:
The answer is the fourth one because 3:4 and 15:20 are equivalent, so there's your answer. Hope it helps!
Answer:
8 months and $320
Step-by-step explanation:
To find when 30m + 80 = 40m, isolate m.
30m + 80 = 40m
Subtract 40m from both sides.
-10m + 80 = 0
Subtract 80 from both sides.
-10m = -80
Divide both sides by -10
m = 8
To find the cost, substitute 8 as m in one of the equations.
40(8) = 320