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tiny-mole [99]
3 years ago
6

Https://m.eet.go.ogle.com/tjc-pyur-uqo anyone can join ^3^

Mathematics
1 answer:
PolarNik [594]3 years ago
8 0

Answer:

noooooooooooooooo

Step-by-step explanation:

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Triangle ABC is similar to triangle WYZ.
LenaWriter [7]

Answer:

∠B

∠Y

Step-by-step explanation:

we know that

In the right triangle ABC

----> opposite side to angle B divided by the adjacent side to angle B

substitute the values

Remember that

If two triangles are similar, then the corresponding sides are proportional and the corresponding angles are congruent

so

∠A=∠W

∠B=∠Y

∠C=∠Z

4 0
2 years ago
Nina made 8 withdrawals from
forsale [732]
The total change in her bank account would be $160,

if you multiply 8x$20 you get $160
6 0
2 years ago
What is true of every rhombus that is also true of every parallelogram?
Elena L [17]

Answer:

A rhombus has two pairs of parallel sides.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A company manufactures and sells x television sets per month. The monthly cost and​ price-demand equations are ​C(x)=74,000+80x
SOVA2 [1]

Answer:

a) $675000

b) $289000 profit,3300 set, $190 per set

c) 3225 set, $272687.5 profit, $192.5 per set

Step-by-step explanation:

a) Revenue R(x) = xp(x) = x(300 - x/30) = 300x - x²/30

The maximum revenue is at R'(x) =0

R'(x) = 300 - 2x/30 = 300 - x/15

But we need to compute R'(x) = 0:

300 - x/15 = 0

x/15 = 300

x = 4500

Also the second derivative of R(x) is given as:

R"(x) = -1/15 < 0 This means that the maximum revenue is at x = 4500. Hence:

R(4500) = 300 (4500) - (4500)²/30 = $675000  

B) Profit P(x) = R(x) - C(x) = 300x - x²/30 - (74000 + 80x) = -x²/30 + 300x - 80x - 74000

P(x) = -x²/30 + 220x - 74000

The maximum revenue is at P'(x) =0

P'(x) = - 2x/30 + 220= -x/15 + 220

But we need to compute P'(x) = 0:

-x/15 + 220 = 0

x/15 = 220

x = 3300

Also the second derivative of P(x) is given as:

P"(x) = -1/15 < 0 This means that the maximum profit is at x = 3300. Hence:

P(3300) =  -(3300)²/30 + 220(3300) - 74000 = $289000  

The price for each set is:

p(3300) = 300 -3300/30 = $190 per set

c) The new cost is:

C(x) = 74000 + 80x + 5x = 74000 + 85x

Profit P(x) = R(x) - C(x) = 300x - x²/30 - (74000 + 85x) = -x²/30 + 300x - 85x - 74000

P(x) = -x²/30 + 215x - 74000

The maximum revenue is at P'(x) =0

P'(x) = - 2x/30 + 215= -x/15 + 215

But we need to compute P'(x) = 0:

-x/15 + 215 = 0

x/15 = 215

x = 3225

Also the second derivative of P(x) is given as:

P"(x) = -1/15 < 0 This means that the maximum profit is at x = 3225. Hence:

P(3225) =  -(3225)²/30 + 215(3225) - 74000 = $272687.5

The money to be charge for each set is:

p(x) = 300 - 3225/30 = $192.5 per set

When taxed $5, the maximum profit is $272687.5

3 0
2 years ago
Haddie makes and sells knit scarves. Next week she will pay a $25 fee for the use of a booth at a craft fair. She will charge $1
Serggg [28]
The answer is 25 + 12x
8 0
3 years ago
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