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3 years ago

Factor (difference of squares) the binomial 25x^2-4 and find one of its factors

Mathematics

1 answer:

Lunna [17]3 years ago

6 0

Step-by-step explanation:

Hey, there!

Here,

Given that:

$= 25 {x}^{2} - 4$

we need to find factor,

As it is in a^2-b^2 form as per its factor (a+b) (a-b), keeping same formula here,

25x^2 means (5x)^2

and 4 means 2^2

Now, it would be,

$= ( {5x)}^{2} - {2}^{2}$

$= (5x + 2)(5x - 2)$

Therefore, it's factor would be (5x+2)(5x-2).

Hope it helps....

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PLEASE PLEASEE ANSWER THE QUESTION IN THE PICTURE BELOW

KatRina [158]

Answer: Choice C

Vertex = (5, -2)

===============================================

Explanation:

Vertex form is $y = a(x-h)^2 + k$ where the vertex itself is located at (h,k)

As the name implies, we can very quickly pull out the coordinates of the vertex without doing much math at all.

In the case of choice C, we have $y= \frac{1}{2}(x-5)^2 - 2$ which is the same as $y = \frac{1}{2}(x-5)^2 + (-2)$ and we can see that h = 5 and k = -2. Therefore, the vertex is located at (h,k) = (5, -2)

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2 years ago

How do you solve sin (5pi/3) without a calculator?

Savatey [412]

very simple, we use the formula sin(a+b)=sinacosb + sinbcosa and sin(20)=2sinacosa

5pi = 2pi/3+3pi/3,

First, we use sin(a+b)=sinacosb + sinbcosa

sin(5pi/3)=sin(2pi/3+3pi/3)= sin(2pi/3+pi)= sin(2pi/3)cos(pi) +sin(pi)cos(2pi/3)

but we know that sin(pi)= 0, and cos (pi) = -1, so sin(5pi/3)= - sin(2pi/3)

now, use sin(2a)=2sinacosa, sin(5pi/3)= - sin(2pi/3)= -2sin(pi/3)cos(pi/3)

sin(5pi/3)= -2sin(pi/3)cos(pi/3)

sin(pi/3)= 0.86, cos(pi/3)=0.5, finally we have sin(5pi/3)= -0.86 x 0.5= -0.43

5 0

3 years ago

Read 2 more answers

I will give u brianliest

lianna [129]

Answer:

10.63

Step-by-step explanation:

8 0

3 years ago

likoan [24]

It's easy to show that $7\tan(4x)$ is strictly increasing on $x\in\left[0,\frac\pi8\right]$ . This means

$M = \max \left\{7\tan(4x) \mid \dfrac\pi{16} \le x \le \dfrac\pi{12}\right\} = 7\tan(4x) \bigg|_{x=\pi/12} = 7\sqrt3$

and

$m = \min \left\{7\tan(4x) \mid \dfrac\pi{16} \le x \le \dfrac\pi{12}\right\} = 7\tan(4x) \bigg|_{x=\pi/16} = 7$

Then the integral is bounded by

$\displaystyle 7\left(\frac\pi{12} - \frac\pi{16}\right) \le \int_{\pi/16}^{\pi/12} 7\tan(4x) \, dx \le 7\sqrt3 \left(\frac\pi{12} - \frac\pi{16}\right)$

$\implies \displaystyle \boxed{\frac{7\pi}{48}} \le \int_{\pi/16}^{\pi/12} 7\tan(4x) \, dx \le \boxed{\frac{7\sqrt3\,\pi}{48}}$

7 0

2 years ago

If 3t=5t-8 evaluate -4t+5

Sergio [31]

3t = 5t - 8

-2t = -8

t = 4

Now put that into -4t + 5:

-4t + 5

-4(4) + 5

-16 + 5

-11

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6 0

3 years ago