Answer: 0.1
Step-by-step explanation:
If we spin a fair spinner numbered 1 - 5 and flips a fair coin.
Then, the possible outcomes will be :-
![(1,T),(2,T), (3,T), (4,T), (5,T)\\\\(1,H),(2,H), (3,H), (4,H), (5,H)](https://tex.z-dn.net/?f=%281%2CT%29%2C%282%2CT%29%2C%20%283%2CT%29%2C%20%284%2CT%29%2C%20%285%2CT%29%5C%5C%5C%5C%281%2CH%29%2C%282%2CH%29%2C%20%283%2CH%29%2C%20%284%2CH%29%2C%20%285%2CH%29)
i.e. total 10 possible outcomes.
The favorable outcomes = a 2 and a head i.e. only 1 .
Now, the probability of obtaining a 2 and a head will be :_
![\dfrac{\text{Number of favorable outcome}}{\text{Total outcomes}}\\\\=\dfrac{1}{10}=0.1](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Ctext%7BNumber%20of%20favorable%20outcome%7D%7D%7B%5Ctext%7BTotal%20outcomes%7D%7D%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B10%7D%3D0.1)
Hence, the probability of obtaining a 2 and a head = 0.1
The average rate of change of function
from x = 3 to x = 4 is 4 times that from x = 1 to x = 2.
The correct option is (A).
What is the average rate of change of a function?
The average rate at which one quantity changes in relation to another's change is referred to as the average rate of change function.
Using function notation, we can define the Average Rate of Change of a function f from a to b as:
![rate(m) = \frac{f(b)-f(a)}{b-a}](https://tex.z-dn.net/?f=rate%28m%29%20%3D%20%5Cfrac%7Bf%28b%29-f%28a%29%7D%7Bb-a%7D)
The given function is
,
Now calculating the average rate of change of function from x = 1 to x = 2.
![m = \frac{g(b)-g(a)}{b-a}\\ m = \frac{g(2)-g(1)}{2-1}\\\\m=\frac{5(2)^{2}-5(2)^1}{2-1}\\ m=\frac{10}{1} \\m=10](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7Bg%28b%29-g%28a%29%7D%7Bb-a%7D%5C%5C%20m%20%3D%20%5Cfrac%7Bg%282%29-g%281%29%7D%7B2-1%7D%5C%5C%5C%5Cm%3D%5Cfrac%7B5%282%29%5E%7B2%7D-5%282%29%5E1%7D%7B2-1%7D%5C%5C%20m%3D%5Cfrac%7B10%7D%7B1%7D%20%5C%5Cm%3D10)
Now, calculate the average rate of change of function from x = 3 to x = 4.
![m = \frac{g(b)-g(a)}{b-a}\\ m = \frac{g(4)-g(3)}{4-3}\\\\m=\frac{5(2)^{4}-5(2)^3}{4-3}\\ m=\frac{40}{1} \\m=40](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7Bg%28b%29-g%28a%29%7D%7Bb-a%7D%5C%5C%20m%20%3D%20%5Cfrac%7Bg%284%29-g%283%29%7D%7B4-3%7D%5C%5C%5C%5Cm%3D%5Cfrac%7B5%282%29%5E%7B4%7D-5%282%29%5E3%7D%7B4-3%7D%5C%5C%20m%3D%5Cfrac%7B40%7D%7B1%7D%20%5C%5Cm%3D40)
The jump from m = 10 to m = 40 is "times 4".
So option (A) is correct.
Hence, The average rate of change of function
from x = 3 to x = 4 is 4 times that from x = 1 to x = 2.
To learn more about the average rate of change of function, visit:
brainly.com/question/24313700
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Answer:
21.73
Step-by-step explanation:
calculator
Answer:
Step-by-step explanation:
v=Q-P
v=(5,1,0)
u=v/(magnitude of v)=(5,1,0)/(\sqrt{5^2+1^2+0^2)
u=(5/5.09,1/5.09,0)
v=Q-P
v=(1,1,0)
u=v/(magnitude of v)=(1,1,0)/(\sqrt{1^2+1^2+0^2)
u=(1/
,1/
,0)
Using the binomial distribution, it is found that there is a 0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.
For each die, there are only two possible outcomes, either a 3 or a 4 is rolled, or it is not. The result of a roll is independent of any other roll, hence, the <em>binomial distribution</em> is used to solve this question.
Binomial probability distribution
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- There are 9 rolls, hence
.
- Of the six sides, 2 are 3 or 4, hence
![p = \frac{2}{6} = 0.3333](https://tex.z-dn.net/?f=p%20%3D%20%5Cfrac%7B2%7D%7B6%7D%20%3D%200.3333)
The desired probability is:
![P(X \geq 2) = 1 - P(X < 2)](https://tex.z-dn.net/?f=P%28X%20%5Cgeq%202%29%20%3D%201%20-%20P%28X%20%3C%202%29)
In which:
![P(X < 2) = P(X = 0) + P(X = 1)](https://tex.z-dn.net/?f=P%28X%20%3C%202%29%20%3D%20P%28X%20%3D%200%29%20%2B%20P%28X%20%3D%201%29)
Then
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
![P(X = 0) = C_{9,0}.(0.3333)^{0}.(0.6667)^{9} = 0.026](https://tex.z-dn.net/?f=P%28X%20%3D%200%29%20%3D%20C_%7B9%2C0%7D.%280.3333%29%5E%7B0%7D.%280.6667%29%5E%7B9%7D%20%3D%200.026)
![P(X = 1) = C_{9,1}.(0.3333)^{1}.(0.6667)^{8} = 0.117](https://tex.z-dn.net/?f=P%28X%20%3D%201%29%20%3D%20C_%7B9%2C1%7D.%280.3333%29%5E%7B1%7D.%280.6667%29%5E%7B8%7D%20%3D%200.117)
Then:
![P(X < 2) = P(X = 0) + P(X = 1) = 0.026 + 0.117 = 0.143](https://tex.z-dn.net/?f=P%28X%20%3C%202%29%20%3D%20P%28X%20%3D%200%29%20%2B%20P%28X%20%3D%201%29%20%3D%200.026%20%2B%200.117%20%3D%200.143)
![P(X \geq 2) = 1 - P(X < 2) = 1 - 0.143 = 0.857](https://tex.z-dn.net/?f=P%28X%20%5Cgeq%202%29%20%3D%201%20-%20P%28X%20%3C%202%29%20%3D%201%20-%200.143%20%3D%200.857)
0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.
For more on the binomial distribution, you can check brainly.com/question/24863377