What is the additive inverse of 18xy?

Mathematics

2 answers:

AlladinOne [14]3 years ago

7 0

The answer to this question is A. -18xy. Good luck.

Cloud [144]3 years ago

6 0

An additive inverse is the value you can add to a given value such that the sum is "0"..

Your answer is choice A
18xy + (-18xy) = 0 Since these are like terms.. the key here is understanding that like terms must have the same exact variables raised to the exact same powers. We can add like terms. We cannot add unlike terms.

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Evaluate the integral by interpreting it in terms of areas Draw a picture of the region the integral

denis23 [38]

Answer:

Step-by-step explanation:

The picture is below of how to separate this into 2 different regions, which you have to because it's not continuous over the whole function. It "breaks" at x = 2. So the way to separate this is to take the integral from x = 0 to x = 2 and then add it to the integral for x = 2 to x = 3. In order to integrate each one of those "parts" of that absolute value function we have to determine the equation for each line that makes up that part.

For the integral from [0, 2], the equation of the line is -3x + 6;

For the integral from [2, 3], the equation of the line is 3x - 6.

We integrate then:

$\int\limits^2_0 {-3x+6} \, dx+\int\limits^3_2 {3x-6} \, dx$ and

$-\frac{3x^2}{2}+6x\left \} {{2} \atop {0}} \right. +\frac{3x^2}{2}-6x\left \} {{3} \atop {2}} \right.$ sorry for the odd representation; that's as good as it gets here!