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Zarrin [17]
3 years ago
14

In a chemical equation, which symbol should be used to indicate that a substance is in solution?

Chemistry
2 answers:
lisabon 2012 [21]3 years ago
5 0
D.) aq(aqueous) symbol is used to represent solution.
Hope this helps!!
Klio2033 [76]3 years ago
5 0

Answer:

The answer is D. (aq)

Explanation:

Hope this helps :)

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frozen [14]

Answer:

oceanic formation is the right answer.

Explanation:

this os becoz they slide a past each other and do not rub against each other

4 0
2 years ago
Questions are in the image B and 4i
Keith_Richards [23]
Dimitri mastered in Elements
7 0
2 years ago
A solution of sulfuric acid has a concentration of 0.0980 g/L. If the density of the acid is 1.84 g/mL, what is the concentratio
mariarad [96]
The answer is 98ppm.

The ppm (Parts per million) is also a concentration unit. 1 ppm is equivalent to 1mg/L
Now, concentration of the solution of sulfuric acid is 0.0980 g/L.
We rewrite, 0.0980 g = 0.0980*1000 mg = 98mg
Therefore, the concentration of the sulfuric acid solution is 98 mg/L = 98 ppm.
6 0
3 years ago
Read 2 more answers
Write the products of these double-replacement reaction. Then balance each equation. a) NaOH(aq) + Fe(NO3)3 (aq)---> Iron (II
pashok25 [27]

Answer:

3NaOH (aq) + Fe(NO₃)₃ (aq) → Fe(OH)₃ (s) + 3NaNO₃ (aq)

Explanation:

Step 1: RxN

NaOH (aq) + Fe(NO₃)₃ (aq) → Fe(OH)₃ (s) + NaNO₃ (aq)

Step 2: Balance RxN

We need 3 OH's on both sides.

We also need 3 NO₃'s on both side.

  • This will make it so we also need 3 Na's on both side

3NaOH (aq) + Fe(NO₃)₃ (aq) → Fe(OH)₃ (s) + 3NaNO₃ (aq)

6 0
2 years ago
Cryogenics has the potential to be useful in a variety of fields, including medicine. Suppose you have engineered a method to su
tatiyna

Explanation:

It is known that the specific heat capacity of Liver (C_{p}) is 3.59 kJ kg^{-1}.K^{-1}

It is given that :

Initial temperature of Liver = Body temperature = 37^{o}C = 310 K

Final temperature of Liver = 180 K

Relation between heat energy, mass, and change in temperature is as follows.

                        Q = m \times C_{p} \times \Delta T

Now, putting the given values into the above formula as follows.

                    Q = m \times C_{p} \times \Delta T

                    Q = 1.5 kg \times 3.59 kJ/kg.K \times (310 - 180) K

                         =  700.05 kJ

Therefore, we can conclude that amount of heat which must be removed from the liver is 700.05 kJ.

7 0
3 years ago
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