Answer:
55.0 g
Explanation:
Step 1: Write the balanced equation for the production of oxygen
2 CO₂(g)⇒ 2 CO(g) + O₂(g)
Step 2: Calculate the mass of oxygen produced over a 2 hour period
The MOXIE produces 10.0 g of oxygen per hour.
2 h × 10.0 g/1 h = 20.0 g
Step 3: Calculate the moles corresponding to 20.0 g of O₂
The molar mass of O₂ is 32.00 g/mol.
20.0 g × 1 mol/32.00 g = 0.625 mol
Step 4: Calculate the number of moles of CO₂ needed to produce 0.625 moles of O₂
The molar ratio of CO₂ to O₂ is 2:1. The moles of CO₂ needed are 2/1 × 0.625 mol = 1.25 mol
Step 5: Calculate the mass corresponding to 1.25 moles of CO₂
The molar mass of CO₂ is 44.01 g/mol.
1.25 mol × 44.01 g/mol = 55.0 g
Answer:
Option 4. loss of electrons, resulting in an increased oxidation number.
Explanation:
Oxidation is a process involving loss of electron(s). When this happens the oxidation number of the atom being oxidised increases. This can be seen when calcium (Ca) reacts with chlorine (Cl2) to form calcium chloride (CaCl2) according to the equation given below:
Ca + Cl2 —> CaCl2
The oxidation number of calcium increases from 0 to +2. This implies that calcium is being oxidised as it loses its electrons. The oxidation number of chlorine decreases from 0 to - 1 as it gains electron.
Now, we can see that the oxidation of calcium i.e lose of electrons increased its oxidation number from 0 to +2.
From the simple illustrations above, we can see clearly that oxidation involves loss of electrons, resulting in an increased oxidation number.
Answer:
The reaction will proceed to the left to attain equilibrium.
Explanation:
The question is missing but I guess it must be about <em>how the reaction will proceed to attain equilibrium.</em>
First, we have to calculate the partial pressures using the ideal gas equation.
Now, we have to calculate the reaction quotient (Qp).
Since Qp > Kp, the reaction will proceed to the left to attain equilibrium.
If the number of atoms stays the same no matter how they are rearranged, then their total weight stays the same. In all physical and chemical changes, the total number of atoms remains the same, hence when substances interact with one another, combine or break apart, the total weight of the system remains the same.
Explanation:
1.
Cu(NO3)2 + 2NaCl(aq) --> CuCl2(aq) + 2NaNO3(aq)
2.
Cu(NO3)2 + 2NaOH(aq) --> Cu(OH)2(s) + 2NaNO3(aq)
A light blue precipitate of Cu(OH)2 is formed and NaNO3 in solution.
3.
Cu(NO3)2(aq) --> Cu2+(aq) + 2NO3^-2(aq)
2NaOH(aq) --> 2Na+(aq) + 2OH-(aq)
Cu2+(aq) + 2OH-(aq) --> Cu(OH)2(aq)
2Na+(aq) + 2NO3^-2(aq) --> 2NaNO3(aq)
4.
The reaction in both Questions 1 and 2 is called Double displacement reaction. A double-replacement reaction exchanges the cations and/or or the anions of two ionic compounds. A precipitation reaction is a double-replacement reaction in which one product is a solid precipitate (precipitated) while the other in solution.
Since the cation and anions in Qustion 1 were exchanged, the same was done for Question 2, hence the identity of the precipitate in Question 2 was got.