The volume is the space it takes up, which would be the same. The mass is measured as the weight, and the steel ball would be significantly heavier. Density is mass/volume, and if the steel has a larger mass, it will therefore have a higher density.
1.0153 x 10^3
essentially, scientific notation requires you to take a very large or very small number and simplify it into the first few digits times 10 raised to the power of x.
Although realistically, there is no practical reason to simplify a number that is already that close to 1.
Answer:
Rate = k [OCl] [I]
Explanation:
OCI+r → or +CI
Experiment [OCI] M I(-M) Rate (M/s)2
1 3.48 x 10-3 5.05 x 10-3 1.34 x 10-3
2 3.48 x 10-3 1.01 x 10-2 2.68 x 10-3
3 6.97 x 10-3 5.05 x 10-3 2.68 x 10-3
4 6.97 x 10-3 1.01 x 10-2 5.36 x 10-3
The table above able shows how the rate of the reaction is affected by changes in concentrations of the reactants.
In experiments 1 and 3, the conc of iodine is constant, however the rate is doubled and so is the conc of OCl. This means that the reaction is in first order with OCl.
In experiments 3 and 4, the conc of OCl is constant, however the rate is doubled and so is the conc of lodine. This means that the reaction is in first order with I.
The rate law is given as;
Rate = k [OCl] [I]
Answer:
5.01 L
Explanation:
my guy i just took the test, it was this one
1.7 liters of water will be produced.
Explanation:
The balanced chemical reaction is:
2H2+ 02⇒ 2H20
Considering the reaction to be at STP (P = 1atm, V= 22.4 L, T = 273.15 K)
the formula used is:
PV = nRT
Where P, R and T remains same only volume and number of moles are different so,
= 
observing the balanced reaction:
mole ratio is 2:2 i.e 1:1
so volume ratio will also be same
so 1.7 litres of water will be produced.
From the reaction it is seen that
1 mole hydrogen react with oxygen to give 1 mole of water at STP.
so, it is found that 1.7 liters of hydrogen gives 1.7 liters of water
