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Ksju [112]
3 years ago
15

How much heat will be absorbed by a 50.3 g piece of aluminum (specific heat = 0.930 J/g・°C) as it changes temperature from 23.0°

C to 67.0°C?
Chemistry
1 answer:
shepuryov [24]3 years ago
8 0

Answer:

quantity of heat= <u>mc</u>*they

=50.3*0.930*(67-23)

=46.779*44

=2058.276

quantity of heat =2058.3kJ

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Answer:

Q=-697.06\ J

Negative sign says that release of heat.

Explanation:

The expression for the calculation of the heat released or absorbed of a process is shown below as:-

Q=m\times C\times \Delta T

Where,  

\Delta H  is the heat released or absorbed

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\Delta T  is the temperature change

Thus, given that:-

Mass = 25.2 g

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\Delta T=9.8-72.1\ ^0C=-62.3\ ^0C

So,  

Q=25.2\times 0.444\times -62.3\ J=-697.06\ J

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nadya68 [22]

Answer:

CaCO₃(s) → CaO(s) + CO₂(g)

Explanation:

The decomposition reaction always make two compounds from one.

The products always have simpler chemical structure, originated from a determined compound. This can happens  spontaneously or by a third party.

A notable example of decomposition is hydrolysis. As for example the case of water, which decomposes and generates oxygen and hydrogen gas

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In this case, the calium carbonate decomposes into CaO and CO₂

These two, are the products of the decomposition.

Of course, the unique reactant is the Calcium Carbonate

The balanced equation is:

CaCO₃(s) → CaO(s) + CO₂(g)

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