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2 years ago

15

How much heat will be absorbed by a 50.3 g piece of aluminum (specific heat = 0.930 J/g･°C) as it changes temperature from 23.0°

C to 67.0°C?

1 answer:

shepuryov [24]2 years ago

8 0

Answer:

quantity of heat= <u>mc</u>*they

=50.3*0.930*(67-23)

=46.779*44

=2058.276

quantity of heat =2058.3kJ

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