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Ksju [112]
3 years ago
15

How much heat will be absorbed by a 50.3 g piece of aluminum (specific heat = 0.930 J/g・°C) as it changes temperature from 23.0°

C to 67.0°C?
Chemistry
1 answer:
shepuryov [24]3 years ago
8 0

Answer:

quantity of heat= <u>mc</u>*they

=50.3*0.930*(67-23)

=46.779*44

=2058.276

quantity of heat =2058.3kJ

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A gas has a pressure of 853.0 millibars at a temperature of 29.0 °C. If the volume is unchanged but the temperature is increased
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The new pressure of the gas that initially have a pressure of 853.0 millibars at a temperature of 29.0 °C is 1011.17 millibars. Details about pressure can be found below.

<h3>How to calculate pressure?</h3>

The pressure of a given gas can be calculated using the following formula:

P1/T1 = P2/T2

Where;

  • P1 = initial pressure = 853.0 millibars
  • P2 = final pressure = ?
  • T1 = initial temperature = 29°C + 273 = 302K
  • T2 = final temperature = 85°C + 273 = 358K

853/302 = P2/358

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305374 = 302P2

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Therefore, the new pressure of the gas that initially have a pressure of 853.0 millibars at a temperature of 29.0 °C is 1011.17 millibars.

Learn more about pressure at: brainly.com/question/15175692

#SPJ1

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